.txt 的内容看起来是乱码,其内容是使用 C 编写的
Contents of a .txt looks gibberish whose content is written using C
出于学习目的,我正在将学生记录写入名为 "record.txt" 的文件中
而且我真的没有发现我的代码有任何问题(在我看来)。
这是我试过的代码:
# include<stdio.h>
# include<stdlib.h>
int main() {
FILE *fp;
char choice = 'y';
struct student {
char name[50];
int rollno;
float percentage;
};
struct student s;
fp = fopen("record.txt", "w");
if(fp == NULL) {
puts("Unable to open the file");
exit(0);
}
while(choice == 'y') {
printf("Enter name, rollno and percentage of student: ");
scanf("%s %d %f", &s.name, &s.rollno, &s.percentage);
fwrite(&s, sizeof(s), 1, fp);
printf("Want to enter another record(y/n): ");
fflush(stdin);
choice = getchar();
}
fclose(fp);
}
输出:
Enter name, rollno and percentage of student: jon
15
87.2
Want to enter another record(y/n): n
--------------------------------
Process exited after 6.154 seconds with return value 0
Press any key to continue . . .
"record.txt" 文件的内容:
jon ÿÿÿÿÿÿÿÿL ù$@ L ff®B
所以,我真正想知道的是名称是按应有的方式写的,但其他值(如 rollno 和百分比)看起来难以理解。为什么会这样?
PS随意编辑问题的标题,因为我没有找到合适的标题。
这是固定码:
# include<stdio.h>
# include<stdlib.h>
int main() {
FILE *fp;
char choice = 'y';
struct student {
char name[50];
int rollno;
float percentage;
};
struct student s;
fp = fopen("record.txt", "w");
if (fp == NULL) {
puts("Unable to open the file");
exit(0);
}
while (choice == 'y') {
printf("Enter name, rollno and percentage of student: ");
scanf("%50s %d %f", &s.name, &s.rollno, &s.percentage);
fprintf(fp, "%s, %d, %f\n", s.name, s.rollno, s.percentage); // !changed
printf("Want to enter another record(y/n): ");
fflush(stdin);
choice = getchar();
}
fclose(fp);
}
特别是这条线
fwrite(&s, sizeof(s), 1, fp);
需要更改。
- 使用
fprintf()
写入人类可读的数据
- 你也不需要
写入结构的位模式,而是访问结构的每个字段
结构。
-> fprintf(fp, "%s, %d, %f\n", s.name, s.rollno, s.percentage);
另外一件小事,如果你使用 scanf("%50s %d %f", &s.name, &s.rollno, &s.percentage);
你限制读取的大小 name
到 50 个字符,防止缓冲区溢出。
出于学习目的,我正在将学生记录写入名为 "record.txt" 的文件中 而且我真的没有发现我的代码有任何问题(在我看来)。
这是我试过的代码:
# include<stdio.h>
# include<stdlib.h>
int main() {
FILE *fp;
char choice = 'y';
struct student {
char name[50];
int rollno;
float percentage;
};
struct student s;
fp = fopen("record.txt", "w");
if(fp == NULL) {
puts("Unable to open the file");
exit(0);
}
while(choice == 'y') {
printf("Enter name, rollno and percentage of student: ");
scanf("%s %d %f", &s.name, &s.rollno, &s.percentage);
fwrite(&s, sizeof(s), 1, fp);
printf("Want to enter another record(y/n): ");
fflush(stdin);
choice = getchar();
}
fclose(fp);
}
输出:
Enter name, rollno and percentage of student: jon
15
87.2
Want to enter another record(y/n): n
--------------------------------
Process exited after 6.154 seconds with return value 0
Press any key to continue . . .
"record.txt" 文件的内容:
jon ÿÿÿÿÿÿÿÿL ù$@ L ff®B
所以,我真正想知道的是名称是按应有的方式写的,但其他值(如 rollno 和百分比)看起来难以理解。为什么会这样?
PS随意编辑问题的标题,因为我没有找到合适的标题。
这是固定码:
# include<stdio.h>
# include<stdlib.h>
int main() {
FILE *fp;
char choice = 'y';
struct student {
char name[50];
int rollno;
float percentage;
};
struct student s;
fp = fopen("record.txt", "w");
if (fp == NULL) {
puts("Unable to open the file");
exit(0);
}
while (choice == 'y') {
printf("Enter name, rollno and percentage of student: ");
scanf("%50s %d %f", &s.name, &s.rollno, &s.percentage);
fprintf(fp, "%s, %d, %f\n", s.name, s.rollno, s.percentage); // !changed
printf("Want to enter another record(y/n): ");
fflush(stdin);
choice = getchar();
}
fclose(fp);
}
特别是这条线
fwrite(&s, sizeof(s), 1, fp);
需要更改。
- 使用
fprintf()
写入人类可读的数据 - 你也不需要 写入结构的位模式,而是访问结构的每个字段 结构。
-> fprintf(fp, "%s, %d, %f\n", s.name, s.rollno, s.percentage);
另外一件小事,如果你使用 scanf("%50s %d %f", &s.name, &s.rollno, &s.percentage);
你限制读取的大小 name
到 50 个字符,防止缓冲区溢出。