include_vars 当 yml 嵌入加密变量时出错

Question

问题类似于

我有一个 Ansible 配置文件，其中包含许多纯文本和一个加密值。

    config_value: "something in plain text"
    another_value: "another plain text value"
    my_secret: !vault |
                          $ANSIBLE_VAULT;1.1;AES256
                          36343434346535636131316538313039386539363337326432336330393734306562336563386335
                          3663323065343330303039655530313833623439616630320a323730613534613338326263386136
                          33313033363737626230343432363764356336346363306466356330633561353831346433333366
                          3964386161306338300a333164333932333539333565303038643462643137663438326664336431
                          66613433396133633039385664366564626231313230383464356537636434646534

我按照以下方式加密变量，描述 here:

ansible-vault encrypt_string --vault-password-file path/to/password testvalue

当运行 include_vars 我收到以下错误消息：

TASK [include_vars] ************************************************************
task path: /var/jenkins_home/workspace/path/to/deploy-playbook.yml:21
 [WARNING]: Failure using method (v2_runner_on_ok) in callback plugin
(<ansible.plugins.callback.default.CallbackModule object at 0x7f37a284fa90>):
u'testvalue' is not JSON serializable
Callback Exception: 
  File "/var/jenkins_home/workspace/path/to/virtualenv/local/lib/python2.7/site-packages/ansible/executor/task_queue_manager.py", line 375, in send_callback
    method(*new_args, **kwargs)
   File "/var/jenkins_home/workspace/path/to/virtualenv/local/lib/python2.7/site-packages/ansible/plugins/callback/default.py", line 100, in v2_runner_on_ok
    msg += " => %s" % (self._dump_results(result._result),)
   File "/var/jenkins_home/workspace/path/to/virtualenv/local/lib/python2.7/site-packages/ansible/plugins/callback/__init__.py", line 107, in _dump_results
    return json.dumps(abridged_result, indent=indent, ensure_ascii=False, sort_keys=sort_keys)
   File "/usr/lib/python2.7/json/__init__.py", line 251, in dumps
    sort_keys=sort_keys, **kw).encode(obj)
   File "/usr/lib/python2.7/json/encoder.py", line 209, in encode
    chunks = list(chunks)
   File "/usr/lib/python2.7/json/encoder.py", line 434, in _iterencode
    for chunk in _iterencode_dict(o, _current_indent_level):
   File "/usr/lib/python2.7/json/encoder.py", line 408, in _iterencode_dict
    for chunk in chunks:
   File "/usr/lib/python2.7/json/encoder.py", line 408, in _iterencode_dict
    for chunk in chunks:
   File "/usr/lib/python2.7/json/encoder.py", line 442, in _iterencode
    o = _default(o)
   File "/usr/lib/python2.7/json/encoder.py", line 184, in default
    raise TypeError(repr(o) + " is not JSON serializable")

我也试过以下命令来加密秘密，但没有成功：

ansible-vault encrypt_string --vault-password-file path/to/password 'testvalue'
ansible-vault encrypt_string --vault-password-file path/to/password "testvalue'
ansible-vault encrypt_string --vault-password-file path/to/password "'testvalue'"

Answer 1

"error message" 实际上并没有阻止秘密 (my_secret) 或同一文件中的任何其他配置值可用。

我之前在 ansible 2.4.2，升级到 2.7.0 解决了这个问题。

include_vars 当 yml 嵌入加密变量时出错

Error during include_vars when yml has embedded encrypted variables

encryption

ansible

ansible-vault