如何显示这样的小计值？

Question

我有一个 table 这样的：-

Branch       SL       Month     Amount1 Amount2 Amount3
    A         1       January    100       0        0
    A         2       February     0       0        0
    A         3       March       80       0        0
    A         4       April        0      10       10
    A         5       May          0       0        0
    A         6       June         0       0        0
    A         7       July         0       0       10
    A         8       August       0      10        0
    A         9       September    0      10        0
    A        10       October     40       0       10
    A        11       November    10      10       10
    A        12       December     0      10       10
    B         1       January      0       0       10
    B         2       February    10      10       10
    B         3       March        0       0       10

现在，我试图按每个分支显示小计，这将给出这样的输出，其中“Subtotal”每 12 行后显示一次，就在月份列“Subtotal 的下方" 是这样写的。并且前 2 列将是空白的，我试图使用 UNION ALL 实现此目的但失败了。

Branch  SL    Month   Amount1     Amount2    Amount3
A        1    January     100           0          0
A        2    February      0           0          0
A        3    March        80           0          0
A        4    April         0          10         10
A        5    May           0           0          0
A        6    June          0           0          0
A        7    July          0           0         10
A        8    August        0          10          0
A        9    September     0          10          0
A        10   October      40           0         10
A        11   November     10          10         10
A        12   December      0          10         10
              Subtotal    230          50         50
B        1    January       0           0         10
B        2    February     10          10         10
B        3    March         0           0         10

Answer 1

一种方法使用grouping sets，但您需要聚合查询。你可以这样写：

select Branch, SL, Month, sum(Amount1), sum(Amount2), sum(Amount3)
from t
group by grouping sets ( (Branch, SL, Month), (branch) );

grouping sets 仅从 2008 年起可用。在早期版本中，您可以这样做：

select t.*
from ((select branch, sl, month, amount1, amount2, amount3
       from t
      ) union all
      (select Branch, null, 'Subtotal', sum(Amount1), sum(Amount2), sum(Amount3)
       from t
       group by branch
      )
     ) t
order by branch,
         (case when sl is not null then 1 else 2 end),
         sl;

Answer 2

试试这个

CREATE TABLE T
(
   Branch VARCHAR(1),
   SL INT,
   Month VARCHAR(3),
   Amount1 INT,
   Amount2 INT,
   Amount3 INT
);

INSERT INTO T VALUES
('A', 1, 'Jan', 10, 0, 10),
('A', 2, 'Feb', 20, 0, 20),
('B', 1, 'Jan', 5, 5, 5),
('B', 2, 'Feb', 20, 0, 20),
('C', 1, 'Jan', 55, 44, 33);

WITH CTE AS
(
  SELECT *
  FROM T
  UNION ALL
  SELECT Branch + ' SubTotal', NULL, 'SubTotal', SUM(Amount1), SUM(Amount2), SUM(Amount3)
  FROM T
  GROUP BY Branch
)
SELECT Branch,
       SL,
       Month,
       Amount1,
       Amount2,
       Amount3
FROM CTE
ORDER BY Branch;

结果：

+------------+----+----------+---------+---------+---------+
|   Branch   | SL |  Month   | Amount1 | Amount2 | Amount3 |
+------------+----+----------+---------+---------+---------+
| A          |  1 | Jan      |      10 |       0 |      10 |
| A          |  2 | Feb      |      20 |       0 |      20 |
| A SubTotal |    | SubTotal |      30 |       0 |      30 |
| B          |  1 | Jan      |       5 |       5 |       5 |
| B          |  2 | Feb      |      20 |       0 |      20 |
| B SubTotal |    | SubTotal |      25 |       5 |      25 |
| C          |  1 | Jan      |      55 |      44 |      33 |
| C SubTotal |    | SubTotal |      55 |      44 |      33 |
+------------+----+----------+---------+---------+---------+

如果你真的需要让 Branch 和 SL 空白 ('') 你可以这样做

WITH CTE AS
(
  SELECT Seq = Branch + 'X1',*
  FROM T
  UNION ALL
  SELECT Branch + 'X2', '', NULL, 'SubTotal', SUM(Amount1), SUM(Amount2), SUM(Amount3)
  FROM T
  GROUP BY Branch
)
SELECT Branch,
       SL,
       Month,
       Amount1,
       Amount2,
       Amount3
FROM CTE
ORDER BY Seq;

并且结果与您的预期结果相同

+--------+----+----------+---------+---------+---------+
| Branch | SL |  Month   | Amount1 | Amount2 | Amount3 |
+--------+----+----------+---------+---------+---------+
| A      |  1 | Jan      |      10 |       0 |      10 |
| A      |  2 | Feb      |      20 |       0 |      20 |
|        |    | SubTotal |      30 |       0 |      30 |
| B      |  1 | Jan      |       5 |       5 |       5 |
| B      |  2 | Feb      |      20 |       0 |      20 |
|        |    | SubTotal |      25 |       5 |      25 |
| C      |  1 | Jan      |      55 |      44 |      33 |
|        |    | SubTotal |      55 |      44 |      33 |
+--------+----+----------+---------+---------+---------+

如何显示这样的小计值？

How to show Sub Total value like this?

sql

sql-server

database

sql-server-2005