如何调整3个线程的控制流程？

Question

// Task 1 -- the main thread
        SimilarityResponse w2vResponse = questionClassifier.compute(questionInfo);

        // Task 2
        String sku = questionInfo.getSku();
        String question = questionInfo.getQuestion();
        Callable<ResponseList> dssmTask = () -> this.dssmCompute(sku, question);
        Future<ResponseList> dssmService = executorService.submit(dssmTask);
        ResponseList dssmResponse;
        try {
            LOGGER.info("start dssm ... {} ", question);
            dssmResponse = dssmService.get(Parameters.getParserTimeLimit(), TimeUnit.MILLISECONDS);
            LOGGER.info("dssmResponse ... {} ", dssmResponse);
        } catch (ExecutionException | InterruptedException e) {
            LOGGER.warn("ExecutionException | InterruptedException");
            e.printStackTrace();
        } catch (TimeoutException te) {
            dssmService.cancel(true);
            LOGGER.warn("DSSM time out for {} {}", sku, question);
        }

        // Task 3
        Callable<ResponseList> stsTask = () -> this.stsCompute(sku, question);
        Future<ResponseList> stsService = executorService.submit(stsTask);
        ResponseList stsResponse;
        try {
            LOGGER.info("start sts ... {} ", question);
            stsResponse = stsService.get(Parameters.getParserTimeLimit(), TimeUnit.MILLISECONDS);
            LOGGER.info("stsResponse ... {} ", stsResponse);
        } catch (ExecutionException | InterruptedException e) {
            LOGGER.warn("ExecutionException | InterruptedException");
            e.printStackTrace();
        } catch (TimeoutException te) {
            stsService.cancel(true);
            LOGGER.warn("STS time out for {} {}", sku, question);
        }

        // Last step == do something for above
        SimilarityResponse ensemble = new SimilarityResponse();
        return ensemble;

在执行最后一步之前，如何确定任务1-3已经完成？目前的代码似乎是先完成Task 1然后直接returns。

Answer 1

您应该使用 CountDownLatch。在您的主线程中创建它的实例并将该实例传递给您的任务（可调用对象）。然后当任务完成时调用 latch.countDown()。在代码的最后一步调用 latch.await() 以等待每个任务完成。它看起来像这样（如果您的可调用对象创建为 lambda）：

final CountDownLatch latch = new CountDownLatch(3);

for(int x = 0; x < 3; x++) {
    service.submit( () -> {
        // do something
        latch.countDown();
    });
}

// in the end wait for tasks to finish
latch.await();

如何调整3个线程的控制流程？

How to adjust this control flow of the 3 threads?

java

executorservice