Symfony PHPUnit - 注入依赖
Symfony PHPUnit - Inject dependency
我想测试这个 TokenProvider
<?php
declare(strict_types=1);
namespace App\Services\Provider;
use App\Repository\UserRepository;
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;
use Lexik\Bundle\JWTAuthenticationBundle\Encoder\JWTEncoderInterface;
use Symfony\Component\Security\Core\Exception\BadCredentialsException;
/**
* Class TokenProvider
* @package App\Services\Provider
*/
class TokenProvider
{
/** @var JWTEncoderInterface */
private $JWTEncoder;
/** @var UserPasswordEncoderInterface */
private $passwordEncoder;
/** @var UserRepository */
private $userRepository;
/**
* TokenProvider constructor.
*
* @param JWTEncoderInterface $JWTEncoder
* @param UserPasswordEncoderInterface $passwordEncoder
* @param UserRepository $userRepository
*/
public function __construct(JWTEncoderInterface $JWTEncoder, UserPasswordEncoderInterface $passwordEncoder, UserRepository $userRepository)
{
$this->JWTEncoder = $JWTEncoder;
$this->passwordEncoder = $passwordEncoder;
$this->userRepository = $userRepository;
}
/**
* @param string $email
* @param string $password
*
* @return string
* @throws \Lexik\Bundle\JWTAuthenticationBundle\Exception\JWTEncodeFailureException
*/
public function getToken(string $email, string $password): string
{
$user = $this->userRepository->findOneBy([
'email' => $email,
]);
if (!$user) {
throw new NotFoundHttpException('User Not Found');
}
$isValid = $this->passwordEncoder->isPasswordValid($user, $password);
if (!$isValid) {
throw new BadCredentialsException();
}
return $this->JWTEncoder->encode([
'email' => $user->getEmail(),
'exp' => time() + 3600 // 1 hour expiration
]);
}
}
这是我的测试。它还没有完成。
我想在我的 testGetToken()
中注入 JWTEncoderInterface $encoder
和 UserPasswordEncoder $passwordEncoder
。
class TokenProviderTest extends TestCase
{
/**
* @throws \Lexik\Bundle\JWTAuthenticationBundle\Exception\JWTEncodeFailureException
*/
public function testGetToken()
{
$this->markTestSkipped();
$JWTEncoder = //TODO;
$passwordEncoder = //TODO;
$tokenProvider = new TokenProvider(
$JWTEncoder,
$passwordEncoder,
new class extends UserRepository{
public function findOneBy(array $criteria, array $orderBy = null)
{
return (new User())
->setEmail('kevin@leroi.com')
->setPassword('password')
;
}
}
);
$token = $tokenProvider->getToken('kevin@leroi.com', 'password');
$this->assertEquals(true, $token);
}
}
在 TestCase 中执行此操作的好方法是什么?
我不想模拟这两个服务,因为我想用 LexikJWTAuthenticationBundle 检查我的令牌是否有效
我建议您扩展 KernelTestCase 并在函数 setUp() 中获取您的依赖项,如下所示:
use Symfony\Bundle\FrameworkBundle\Test\KernelTestCase;
class TokenProviderTest extends KernelTestCase
{
private $jWTEncoder
protected function setUp()
{
self::bootKernel();
$this->jWTEncoder = self::$container->get('App\Services\TokenProvider');
}
public function testGetToken()
{
//Your code
}
}
这对你有帮助吗:https://symfony.com/doc/current/testing/doctrine.html#functional-testing
当我不断收到以下弃用警告时,我遇到了这个答案:
1x: Since symfony/twig-bundle 5.2: Accessing the "twig" service directly from the container is deprecated, use dependency injection instead.
1x in ExtensionTest::testIconsExtension from App\Tests\Templates\Icons
我使用以下方法解决了这个问题:
static::bootKernel();
$container = self::$kernel->getContainer()->get('test.service_container');
$twig = $container->get('twig');
所述
我在测试捆绑包时遇到了与@someonewithpc 相同的错误,扩展了测试中的 Kernel
。 test.service_container
服务不可用。
我必须将 framework.test
设置为 true
以获得 FrameworkBundle
:
/**
* This is not the full class, unrelated code have been removed for clarity
*/
class MyBundleTestKernel extends Kernel
{
public function registerBundles()
{
return [
new FrameworkBundle(),
new MyBundle(),
];
}
public function registerContainerConfiguration(LoaderInterface $loader)
{
$loader->load(function (ContainerBuilder $container) {
$container->prependExtensionConfig('framework', ['test' => true]);
});
}
}
我想测试这个 TokenProvider
<?php
declare(strict_types=1);
namespace App\Services\Provider;
use App\Repository\UserRepository;
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;
use Lexik\Bundle\JWTAuthenticationBundle\Encoder\JWTEncoderInterface;
use Symfony\Component\Security\Core\Exception\BadCredentialsException;
/**
* Class TokenProvider
* @package App\Services\Provider
*/
class TokenProvider
{
/** @var JWTEncoderInterface */
private $JWTEncoder;
/** @var UserPasswordEncoderInterface */
private $passwordEncoder;
/** @var UserRepository */
private $userRepository;
/**
* TokenProvider constructor.
*
* @param JWTEncoderInterface $JWTEncoder
* @param UserPasswordEncoderInterface $passwordEncoder
* @param UserRepository $userRepository
*/
public function __construct(JWTEncoderInterface $JWTEncoder, UserPasswordEncoderInterface $passwordEncoder, UserRepository $userRepository)
{
$this->JWTEncoder = $JWTEncoder;
$this->passwordEncoder = $passwordEncoder;
$this->userRepository = $userRepository;
}
/**
* @param string $email
* @param string $password
*
* @return string
* @throws \Lexik\Bundle\JWTAuthenticationBundle\Exception\JWTEncodeFailureException
*/
public function getToken(string $email, string $password): string
{
$user = $this->userRepository->findOneBy([
'email' => $email,
]);
if (!$user) {
throw new NotFoundHttpException('User Not Found');
}
$isValid = $this->passwordEncoder->isPasswordValid($user, $password);
if (!$isValid) {
throw new BadCredentialsException();
}
return $this->JWTEncoder->encode([
'email' => $user->getEmail(),
'exp' => time() + 3600 // 1 hour expiration
]);
}
}
这是我的测试。它还没有完成。
我想在我的 testGetToken()
中注入 JWTEncoderInterface $encoder
和 UserPasswordEncoder $passwordEncoder
。
class TokenProviderTest extends TestCase
{
/**
* @throws \Lexik\Bundle\JWTAuthenticationBundle\Exception\JWTEncodeFailureException
*/
public function testGetToken()
{
$this->markTestSkipped();
$JWTEncoder = //TODO;
$passwordEncoder = //TODO;
$tokenProvider = new TokenProvider(
$JWTEncoder,
$passwordEncoder,
new class extends UserRepository{
public function findOneBy(array $criteria, array $orderBy = null)
{
return (new User())
->setEmail('kevin@leroi.com')
->setPassword('password')
;
}
}
);
$token = $tokenProvider->getToken('kevin@leroi.com', 'password');
$this->assertEquals(true, $token);
}
}
在 TestCase 中执行此操作的好方法是什么?
我不想模拟这两个服务,因为我想用 LexikJWTAuthenticationBundle 检查我的令牌是否有效
我建议您扩展 KernelTestCase 并在函数 setUp() 中获取您的依赖项,如下所示:
use Symfony\Bundle\FrameworkBundle\Test\KernelTestCase;
class TokenProviderTest extends KernelTestCase
{
private $jWTEncoder
protected function setUp()
{
self::bootKernel();
$this->jWTEncoder = self::$container->get('App\Services\TokenProvider');
}
public function testGetToken()
{
//Your code
}
}
这对你有帮助吗:https://symfony.com/doc/current/testing/doctrine.html#functional-testing
当我不断收到以下弃用警告时,我遇到了这个答案:
1x: Since symfony/twig-bundle 5.2: Accessing the "twig" service directly from the container is deprecated, use dependency injection instead.
1x in ExtensionTest::testIconsExtension from App\Tests\Templates\Icons
我使用以下方法解决了这个问题:
static::bootKernel();
$container = self::$kernel->getContainer()->get('test.service_container');
$twig = $container->get('twig');
所述
我在测试捆绑包时遇到了与@someonewithpc 相同的错误,扩展了测试中的 Kernel
。 test.service_container
服务不可用。
我必须将 framework.test
设置为 true
以获得 FrameworkBundle
:
/**
* This is not the full class, unrelated code have been removed for clarity
*/
class MyBundleTestKernel extends Kernel
{
public function registerBundles()
{
return [
new FrameworkBundle(),
new MyBundle(),
];
}
public function registerContainerConfiguration(LoaderInterface $loader)
{
$loader->load(function (ContainerBuilder $container) {
$container->prependExtensionConfig('framework', ['test' => true]);
});
}
}