无法运行在 java 中休息 api

Question

我已经创建了动态 web 项目并将所有 jaxrs-ri jar 文件添加到 lib folder.The 添加的图像将显示我的项目结构。我已经在我的系统上配置了 tomcat 8.0 并且配置正确。这些是文件。

LoginPage.java

package com.login;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

@Path("/loginpage")
public class LoginPage {

    @GET
    @Produces(MediaType.TEXT_PLAIN)
    public String sayPlainTextHello() {
        return "Hello World RESTful Jersey!";
    }

    @GET
    @Produces(MediaType.TEXT_XML)
    public String sayXMLHello() {
        return "<?xml version=\"1.0\"?>" + "<hello> Hello World RESTful Jersey"
                + "</hello>";
    }

    @GET
    @Produces(MediaType.TEXT_HTML)
    public String sayHtmlHello() {
        return "<html> " + "<title>" + "Hello World RESTful Jersey"
                + "</title>" + "<body><h1>" + "Hello World RESTful Jersey"
                + "</body></h1>" + "</html> ";
    }

}

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>LoginForm</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
    <welcome-file>index.htm</welcome-file>
    <welcome-file>index.jsp</welcome-file>
    <welcome-file>default.html</welcome-file>
    <welcome-file>default.htm</welcome-file>
    <welcome-file>default.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
    <servlet-name>RESTful Jersey Hello World Service</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>jersey.config.server.provider.packages</param-name>
        <param-value>com.javapapers.webservices.rest.jersey</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>RESTful Jersey Hello World Service</servlet-name>
    <url-pattern>/rest/*</url-pattern>
  </servlet-mapping>
</web-app>

控制台消息

项目结构

Answer 1

你必须像

一样在servlet.xml中声明控制器class的包名

<context:component-scan base-package="com.dibyendu.controller"></context:component- 
scan> and use @Controller or @RestController in the LoginPage class so that it can be 
considered as Controller.

Answer 2

行

<param-value>com.javapapers.webservices.rest.jersey</param-value>

应该阅读

<param-value>com.login</param-value>

这是您拥有根资源的地方...

无法运行在 java 中休息 api

not able to run rest api in java

java

rest

jersey

tomcat8

无法 运行 在 java 中休息 api

not able to run rest api in java

java

rest

jersey

tomcat8

无法运行在 java 中休息 api