查找 SQL 中 15 天的所有活跃用户

Question

我有两个 table：users、user_source_history。

在tableusers中，保存了所有注册过的用户。并且，在 table user_source_history 中，存储了他们的活动。这些活动可能包括登录系统、订购东西。所以一个用户可以在 user_source_history 中存在多次。

现在的问题是我需要在 15 天的存储桶中找到所有活跃用户。

所以，例如，用户在 2014-12-03 购买了东西。现在，该用户将显示为活跃用户，直到 2014-12-18。

我需要找到日期范围内的所有活跃用户。

因此，例如，在这个日期范围内-

2014-12-03 - 10 users are active.
2014-12-04 - 10(active on 2014-12-03) + (new users for this date)
2014-12-05 - Number on active user on this date + all users in 15 day bucket 
2014-12-06 - Number on active user on this date + all users in 15 day bucket

查询：

SELECT CAST(`user_last_interaction_date` as Date)
FROM `users` U
    LEFT JOIN `user_source_history` USH on U.user_id = USH.user_id
WHERE  `user_last_interaction_date` > 
    (SELECT DATE_ADD(`user_last_interaction_date`, INTERVAL -15 DAY) 
     FROM `users`
     GROUP BY CAST(`user_last_interaction_date` as Date)
    )
GROUP BY CAST(`user_last_interaction_date` as Date)

我试过这个查询，但是 SQL 说 Subquery returns more than one row

如何将查询拆分为运行多行？

Answer 1

下面是一个查询在过去 15 天内活跃的用户的示例：

select  distinct name
from    users u
join    user_source_history uh
on      uh.user_id = u.user_id
where   user_last_interaction_date between
            now() and now() - interval 15 day

Answer 2

这是查找从“2015-05-03”到“2015-05-18”期间没有活跃用户的查询

您需要使用 calendar_date 生成所有日期，它可以是您数据库架构中的日期字段。

SELECT c.calendar_date, count(*) active_users  
FROM `users` U 
LEFT JOIN `user_source_history` USH 
 on( U.user_id = USH.user_id )
CROSS JOIN (select * from
(select adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) `calendar_date`  from
 (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
 (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
 (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
 (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
 (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
where calendar_date between '2015-05-03' and '2015-05-18') as c 
on 
(date(USH.user_last_interaction_date) < c.calendar_date
and date(USH.user_last_interaction_date) >= (SELECT DATE_ADD(c.calendar_date, INTERVAL -15 DAY)))
group by c.calendar_date

查找 SQL 中 15 天的所有活跃用户

To find all the active users in a bucket of 15 days in SQL

mysql

sql

nested-queries