Laravel Collection Return

Question

我想弄清楚为什么 laravel 5.6 当你有一个 collection 时它打印出 json 响应比你使用正常的 return 响应分页json 在分页列表中。所以我现在 returning 在我的 collection.

中

{
"data": [],
"links": {
    "first": "http://local/api/v3/x?=1",
    "last": "http://local/api/v3/x?=1",
    "prev": null,
    "next": null
},
"meta": {
    "current_page": 1,
    "from": 1,
    "last_page": 1,
    "path": "http://local/api/v3/x",
    "per_page": "5",
    "to": 3,
    "total": 3
}
}

我希望它看起来像：

{
"current_page": 1,
"data": [],
"first_page_url": "http://local/api/v3/x?=1",
"from": null,
"last_page": 1,
"last_page_url": "http://local/api/v3/x?=1",
"next_page_url": null,
"path": "http://local/api/v3/x",
"per_page": 50,
"prev_page_url": null,
"to": null,
"total": 0
}

我尝试在 collection 中使用以下代码，但它不起作用，我找到了一些函数来获取我想要的数据，但我仍然缺少大部分数据。

<?php

namespace App\Http\Resources\V3;

use Illuminate\Http\Resources\Json\ResourceCollection;

class DeedTypeCollection extends ResourceCollection
{
public $collects = 'App\Http\Resources\V3\x';

/**
 * Transform the resource collection into an array.
 *
 * @param  \Illuminate\Http\Request  $request
 * @return array
 */
public function toArray($request)
{
    return [
        'current_page' => $this->currentPage(),
        'data' => $this->collection,
        'first_page_url' => $this->links['first'],
        'from' => $this->meta['from'],
        'last_page' => $this->meta['last_page'],
        'last_page_url' => $this->links['last'],
        'next_page_url' => $this->links['next'],
        'path' => $this->meta['path'],
        'per_page' => $this->meta['per_page'],
        'prev_page_url' => $this->links['prev'],
        'to' => $this->meta['to'],
        'total' => $this->meta['total']
    ];
}
}

为什么 laravel 会更改 collection 上的默认分页以及如何解决此问题以匹配 default/second 数据集。

这里是构建查询的地方。

/**
 *  Function: prepareIndexSelect.
 *
 *  @param: $request - Request sent to controller
 *
 *  Description: Returns queried collection.
 */
public static function prepareIndexSelect($request)
{
    $model = new self();
    $per_page = 50;
    $page = 1;
    $order_by = $model->getKeyName();
    $sort_by = 'asc';

    if ($request->has('per_page')) {
        $per_page = $request->input('per_page');
    }

    if ($request->has('sortBy')) {
        $order_by = $request->input('sortBy');
    }

    if ($request->has('sortByAsc')) {
        $sort_by = $request->input('sortByAsc');
    }

    if ($request->has('page')) {
        $page = $request->input('page');
    }

    return $model->when($request->has('fields'), function ($query) use ($request) {
        self::prepareSelectColumns($query, $request->input('fields'));
    })->when($request->has('includes'), function ($query) use ($request) {
        self::prepareIncludedTables($query, $request->input('includes'));
    })->whereSearch($request->input('search'))
    ->orderBy("{$order_by}", "{$sort_by}")
    ->paginate($per_page, null, null, $page);
}

Answer 1

查看文档，您似乎需要 return 在相应端点处派生集合。

您的衍生资源合集：

<?php

namespace App\Http\Resources;

use Illuminate\Http\Resources\Json\ResourceCollection;

class DeedTypeCollection extends ResourceCollection
{
    /**
     * Transform the resource collection into an array.
     *
     * @param  \Illuminate\Http\Request
     * @return array
     */
    public function toArray($request)
    {
        return [
            'current_page' => $this->currentPage(),
            'data' => $this->collection,
            'first_page_url' => $this->links['first'],
            'from' => $this->meta['from'],
            'last_page' => $this->meta['last_page'],
            'last_page_url' => $this->links['last'],
            'next_page_url' => $this->links['next'],
            'path' => $this->meta['path'],
            'per_page' => $this->meta['per_page'],
            'prev_page_url' => $this->links['prev'],
            'to' => $this->meta['to'],
            'total' => $this->meta['total']
        ];
    }
}

您的端点：

use App\DeedType;
use App\Http\Resources\DeedTypeCollection;

Route::get('/deed-types', function () {
    return new DeedTypeCollection(DeedType::all());
});

您也可以扩展 PaginatedResourceResponse 这应该允许您覆盖 paginationInformation 以按照您需要的方式格式化响应。

protected function paginationInformation($request)
{
    return $this->resource->resource->toArray();
}

然后在您的派生集合中：

public function toResponse($request)
{
    return (new MyDerivedPaginatedResourceResponse($this))->toResponse($request)
}

Laravel Collection Return

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