在圆圈内绘制正方形布局
Drawing a square layout inside a circle
我想在一个圆圈内做一个相对布局,即相对布局应该如下图所示的正方形。
我正在尝试将布局的宽度和高度设置为:
√((diameter)²/2)
大约是 70 %
(来源:yogaflavoredlife.com)
public class SquareLayout extends RelativeLayout {
public SquareLayout(Context context, AttributeSet attrs) {
super(context, attrs);
}
@Override
protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
int originalWidth = MeasureSpec.getSize(widthMeasureSpec);
int originalHeight = MeasureSpec.getSize(heightMeasureSpec);
int required = Math.min(originalWidth, originalHeight) * 7 / 10;
super.onMeasure(widthMeasureSpec, heightMeasureSpec);
setMeasuredDimension(required, required);
}
}
我得到的是矩形布局而不是方形布局:
谁能指导我哪里出错了?
示例用法:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent">
<com.example.widget.SquareLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#F55C5C">
</com.example.widget.SquareLayout>
</RelativeLayout>
这是我得到解决方案的方法。首先,我创建了一个方形框架来容纳所有布局。
public class SquareFrame extends FrameLayout {
public SquareFrame(Context context, AttributeSet attrs) {
super(context, attrs);
}
@Override
protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
int originalWidth = MeasureSpec.getSize(widthMeasureSpec);
int originalHeight = MeasureSpec.getSize(heightMeasureSpec);
int required = Math.min(originalWidth, originalHeight);
super.onMeasure(
MeasureSpec.makeMeasureSpec(required, MeasureSpec.EXACTLY),
MeasureSpec.makeMeasureSpec(required, MeasureSpec.EXACTLY));
}
}
然后将所有布局插入该方形框架内。
<com.example.widget.SquareFrame
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#5CF5FC">
<com.example.widget.SquareLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#F55C5C">
</com.example.widget.SquareLayout>
</com.example.widget.SquareFrame>
这是我得到的
正方形,不是长方形。
我想在一个圆圈内做一个相对布局,即相对布局应该如下图所示的正方形。
我正在尝试将布局的宽度和高度设置为:
√((diameter)²/2)
大约是 70 %
(来源:yogaflavoredlife.com)
public class SquareLayout extends RelativeLayout {
public SquareLayout(Context context, AttributeSet attrs) {
super(context, attrs);
}
@Override
protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
int originalWidth = MeasureSpec.getSize(widthMeasureSpec);
int originalHeight = MeasureSpec.getSize(heightMeasureSpec);
int required = Math.min(originalWidth, originalHeight) * 7 / 10;
super.onMeasure(widthMeasureSpec, heightMeasureSpec);
setMeasuredDimension(required, required);
}
}
我得到的是矩形布局而不是方形布局:
谁能指导我哪里出错了?
示例用法:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent">
<com.example.widget.SquareLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#F55C5C">
</com.example.widget.SquareLayout>
</RelativeLayout>
这是我得到解决方案的方法。首先,我创建了一个方形框架来容纳所有布局。
public class SquareFrame extends FrameLayout {
public SquareFrame(Context context, AttributeSet attrs) {
super(context, attrs);
}
@Override
protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
int originalWidth = MeasureSpec.getSize(widthMeasureSpec);
int originalHeight = MeasureSpec.getSize(heightMeasureSpec);
int required = Math.min(originalWidth, originalHeight);
super.onMeasure(
MeasureSpec.makeMeasureSpec(required, MeasureSpec.EXACTLY),
MeasureSpec.makeMeasureSpec(required, MeasureSpec.EXACTLY));
}
}
然后将所有布局插入该方形框架内。
<com.example.widget.SquareFrame
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#5CF5FC">
<com.example.widget.SquareLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="#F55C5C">
</com.example.widget.SquareLayout>
</com.example.widget.SquareFrame>
这是我得到的