feathers-mongodb Service.find({query: {_id}}) returns 空

Question

我有以下架构：

students.graphql.schema.js

export default [
  `
  type StudentsWithPagination {
    total: Int
    items: [Students]
  }

  type Students {
    _id: String!
    name: String
    address: Addresses
  }
`,
];

addresses.graphql.schema.js

export default [
      `
  type AddressesWithPagination {
    total: Int
    items: [Addresses]
  }

  type Addresses {
    _id: String!
    title: String
  }
`,
];

我已经通过运行 feathers generate service students.service.js 和 addresses.services.js[=52 创建了两个服务=].

当我通过 title 搜索地址时，我得到了结果。但是，当我按 _id 搜索时，我得到空值。类似于：

const studentsResolvers = { Students: { address: student => { const query = { _id: student.address } return Addresses.find({ query }).then(result => { console.log(result) }) } } }

上面的代码产生了 null 而 student.address return 是正确的 address._id。我仍然得到 null 即使我用正确的 address._id
硬编码 student.address
除非我按地址标题搜索，否则上面的代码将 return null。类似于：

const query = { title: 'my-location' }

_id 是 String 类型，而不是 ObjectID。

我做错了什么？

Answer 1

作为 documented in the feathers-mongodb adapter, since MongoDB itself (unlike Mongoose) does not have a schema, all query parameters have to be converted to the type in the database in a hook 手动。该示例可以相应地适应 $in 查询：

const ObjectID = require('mongodb').ObjectID;

app.service('users').hooks({
  before: {
    find(context) {
      const { query = {} } = context.params;

      if(query._id) {
        query._id  = new ObjectID(query._id);
      }

      if(query.age !== undefined) {
        query.age = parseInt(query.age, 10);
      }

      context.params.query = query;

      return Promise.resolve(context);
    }
  }
});

feathers-mongodb Service.find({query: {_id}}) returns 空

feathers-mongodb Service.find({query: {_id}}) returns null

mongodb

graphql

feathersjs