Jet/ACE SQL, iif 语句,同一列有 2 个假值

Jet/ACE SQL, iif statement, 2 false values same column

我在 excel.

的 sql 查询中有以下 iif 语句
iif(master.[Canada] = '0' or master.[Canada] = ' ' or master.[Canada] IS NULL,master.[USA], master.[Canada]) as Whosebug

但我想添加类似 iff([Whosebug] is not null, [Whosebug], "n/a") as Whosebug 但不能有重复的别名'。

有谁知道两个假条件怎么做?我需要让 Whosebug 列中的空白显示为 N/a.

逻辑是这样的,

+--------+--------+---------------+
| Canada |  USA   | Whosebug |
+--------+--------+---------------+
|  12345 |  35262 |         12345 |
|  15678 |  52367 |         15678 |
|        |  97536 |         97536 |
|  17893 |  35252 |         17893 |
|      0 | 120321 |        120321 |
+--------+--------+---------------+

但是如果 Whosebug 为空怎么办,我想把 n/a 放在那里

尝试类似的东西:

iff(master.[Canada] <> ' ', iif(master.[Canada] = '0' or master.[Canada] = ' ' or master.[Canada] IS NULL,master.[USA], master.[Canada]), "n/a") as best_id

但是无法让它工作。 undefined funcation iif

试试这个

iif([Whosebug] is not null, iif(Nz(master.[Canada],'0') = '0' or master.[Canada] = ' ',master.[USA], master.[Canada]) , "n/a") as Whosebug1

使用嵌套 IIF() 时,必须使右括号的数量与左括号的数量相等。下面缩进了每个IIF()表达式真实部分虚假部分以强调:

IIF(master.[Canada] <> '0' AND TRIM(master.[Canada]) <> '' AND master.[Canada] IS NOT NULL, 
    master.[Canada], 
    IIF(master.[USA] <> '0' AND TRIM(master.[USA]) <> '' AND master.[USA] IS NOT NULL, 
        master.[USA], 
        'n/a'
       )
   ) as Whosebug