JQuery Datepicker - 根据当前时间设置 MinDate
JQuery Datepicker - setting MinDate based on current time
我正在使用 JQuery 日期选择器供客户选择交货日期。我希望能够检查客户是否在中午之前订购,如果是,则可以在第二天交货。如果他们在中午之后订购,则无法提供次日送达,因此无法选择当天。
我有一些代码可以检查当前时间,但是如何将这个值添加到顶部设置中的 MinDate 中?
谢谢!
<div class="delivery-date">
<p>
<label for="date">Select a date for delivery below:</label>
<input id="date" type="text" name="properties[delivery-date]" readonly="readonly" style="background:white; width:30%" class="required" data-error="Please choose a delivery date." />
</p>
</div>
<script>
jQuery(function() {
jQuery("#date").datepicker( {
// minDate: new Date(((new Date).getTime() + 49 * 60 * 60 * 1000) ),
minDate: checkBeforeNoon,
maxDate: "+2M", // show up to 2 months
dateFormat: 'dd/mm/yy',
beforeShowDay: available_delivery_dates
} );
});
/*========== check time ==========*/
// if time before 12pm, offer next day delivery
function checkBeforeNoon(nextDayDelivery){
var startTime = '12:00 AM';
var endTime = '12:00 PM';
var curr_time = getval();
if (get24Hr(curr_time) > get24Hr(startTime) && get24Hr(curr_time) < get24Hr(endTime)) {
// before 12pm - next day delivery available
var nextDayDelivery = '+1d';
} else {
// after 12pm - next day delivery unavailable
var nextDayDelivery = '+2d';
}
function get24Hr(time){
var hours = Number(time.match(/^(\d+)/)[1]);
var AMPM = time.match(/\s(.*)$/)[1];
if(AMPM == "PM" && hours<12) hours = hours+12;
if(AMPM == "AM" && hours==12) hours = hours-12;
var minutes = Number(time.match(/:(\d+)/)[1]);
hours = hours*100+minutes;
console.log(time +" - "+hours);
return hours;
}
function getval() {
var currentTime = new Date()
var hours = currentTime.getHours()
var minutes = currentTime.getMinutes()
if (minutes < 10) minutes = "0" + minutes;
var suffix = "AM";
if (hours >= 12) {
suffix = "PM";
hours = hours - 12;
}
if (hours == 0) {
hours = 12;
}
var current_time = hours + ":" + minutes + " " + suffix;
return current_time;
}
}
/*========== Make sundays always unavailable ==========*/
function available_delivery_dates(date) {
var sunday = 0; // unavailable for delivery
var mon = 1
var tue = 2;
var wed = 3;
var thu = 4;
var fri = 5;
var sat = 6;
var day_of_week = date.getDay();
var not_sun = day_of_week > 0;
if(not_sun){
var day = date.getDate();
return [true, ''];
}
else{
// all else - do not allow
return [false, ' ', 'Delivery is unavailable on this day'];
}
}
</script>
你已经做到了。您只需向检查是否是中午的函数添加一个 return。如果你想通知客户现在可以一天发货,你可以通过在你的函数中添加一个日志来实现。这是您修改的代码:
http://jsfiddle.net/graphicfreedom/L3tz8243/1/
function checkBeforeNoon(nextDayDelivery){
var startTime = '12:00 AM';
var endTime = '12:00 PM';
var curr_time = getval();
if (get24Hr(curr_time) > get24Hr(startTime) && get24Hr(curr_time) < get24Hr(endTime)) {
// before 12pm - next day delivery available
var nextDayDelivery = '+1d';
$("#log").html('Next day delivery available! Order before noon!'); //show response to user
} else {
// after 12pm - next day delivery unavailable
var nextDayDelivery = '+2d';
$("#log").html('Next day delivery NOT available! It is already past noon :('); //show response to user
}
return nextDayDelivery;
}
此外,您可以轻松地将功能分开。它更易于阅读,并且您始终可以从函数中调用函数。希望这对您有所帮助!
删除 if-else
块中 nextDayDelivery
之前的 var
,因为您将重新声明它。然后returnnextDayDelivery
。另外,修复 getVal()
方法中缺少的分号是个好主意。
function checkBeforeNoon(nextDayDelivery) {
var startTime = '12:00 AM';
var endTime = '12:00 PM';
var curr_time = getval();
if (get24Hr(curr_time) > get24Hr(startTime) && get24Hr(curr_time) < get24Hr(endTime)) {
// before 12pm - next day delivery available
nextDayDelivery = '+1d'; // REMOVE var FROM HERE
} else {
// after 12pm - next day delivery unavailable
nextDayDelivery = '+2d'; // REMOVE var FROM HERE
}
function get24Hr(time) {
var hours = Number(time.match(/^(\d+)/)[1]);
var AMPM = time.match(/\s(.*)$/)[1];
if (AMPM == "PM" && hours < 12) hours = hours + 12;
if (AMPM == "AM" && hours == 12) hours = hours - 12;
var minutes = Number(time.match(/:(\d+)/)[1]);
hours = hours * 100 + minutes;
console.log(time + " - " + hours);
return hours;
}
function getval() {
// ADD MISSING SEMI-COLONS ON THE FOLLOWING 3 LINES
var currentTime = new Date();
var hours = currentTime.getHours();
var minutes = currentTime.getMinutes();
if (minutes < 10) minutes = "0" + minutes;
var suffix = "AM";
if (hours >= 12) {
suffix = "PM";
hours = hours - 12;
}
if (hours == 0) {
hours = 12;
}
var current_time = hours + ":" + minutes + " " + suffix;
return current_time;
}
return nextDayDelivery; // ADD RETURN STATEMENT
}
我正在使用 JQuery 日期选择器供客户选择交货日期。我希望能够检查客户是否在中午之前订购,如果是,则可以在第二天交货。如果他们在中午之后订购,则无法提供次日送达,因此无法选择当天。
我有一些代码可以检查当前时间,但是如何将这个值添加到顶部设置中的 MinDate 中?
谢谢!
<div class="delivery-date">
<p>
<label for="date">Select a date for delivery below:</label>
<input id="date" type="text" name="properties[delivery-date]" readonly="readonly" style="background:white; width:30%" class="required" data-error="Please choose a delivery date." />
</p>
</div>
<script>
jQuery(function() {
jQuery("#date").datepicker( {
// minDate: new Date(((new Date).getTime() + 49 * 60 * 60 * 1000) ),
minDate: checkBeforeNoon,
maxDate: "+2M", // show up to 2 months
dateFormat: 'dd/mm/yy',
beforeShowDay: available_delivery_dates
} );
});
/*========== check time ==========*/
// if time before 12pm, offer next day delivery
function checkBeforeNoon(nextDayDelivery){
var startTime = '12:00 AM';
var endTime = '12:00 PM';
var curr_time = getval();
if (get24Hr(curr_time) > get24Hr(startTime) && get24Hr(curr_time) < get24Hr(endTime)) {
// before 12pm - next day delivery available
var nextDayDelivery = '+1d';
} else {
// after 12pm - next day delivery unavailable
var nextDayDelivery = '+2d';
}
function get24Hr(time){
var hours = Number(time.match(/^(\d+)/)[1]);
var AMPM = time.match(/\s(.*)$/)[1];
if(AMPM == "PM" && hours<12) hours = hours+12;
if(AMPM == "AM" && hours==12) hours = hours-12;
var minutes = Number(time.match(/:(\d+)/)[1]);
hours = hours*100+minutes;
console.log(time +" - "+hours);
return hours;
}
function getval() {
var currentTime = new Date()
var hours = currentTime.getHours()
var minutes = currentTime.getMinutes()
if (minutes < 10) minutes = "0" + minutes;
var suffix = "AM";
if (hours >= 12) {
suffix = "PM";
hours = hours - 12;
}
if (hours == 0) {
hours = 12;
}
var current_time = hours + ":" + minutes + " " + suffix;
return current_time;
}
}
/*========== Make sundays always unavailable ==========*/
function available_delivery_dates(date) {
var sunday = 0; // unavailable for delivery
var mon = 1
var tue = 2;
var wed = 3;
var thu = 4;
var fri = 5;
var sat = 6;
var day_of_week = date.getDay();
var not_sun = day_of_week > 0;
if(not_sun){
var day = date.getDate();
return [true, ''];
}
else{
// all else - do not allow
return [false, ' ', 'Delivery is unavailable on this day'];
}
}
</script>
你已经做到了。您只需向检查是否是中午的函数添加一个 return。如果你想通知客户现在可以一天发货,你可以通过在你的函数中添加一个日志来实现。这是您修改的代码:
http://jsfiddle.net/graphicfreedom/L3tz8243/1/
function checkBeforeNoon(nextDayDelivery){
var startTime = '12:00 AM';
var endTime = '12:00 PM';
var curr_time = getval();
if (get24Hr(curr_time) > get24Hr(startTime) && get24Hr(curr_time) < get24Hr(endTime)) {
// before 12pm - next day delivery available
var nextDayDelivery = '+1d';
$("#log").html('Next day delivery available! Order before noon!'); //show response to user
} else {
// after 12pm - next day delivery unavailable
var nextDayDelivery = '+2d';
$("#log").html('Next day delivery NOT available! It is already past noon :('); //show response to user
}
return nextDayDelivery;
}
此外,您可以轻松地将功能分开。它更易于阅读,并且您始终可以从函数中调用函数。希望这对您有所帮助!
删除 if-else
块中 nextDayDelivery
之前的 var
,因为您将重新声明它。然后returnnextDayDelivery
。另外,修复 getVal()
方法中缺少的分号是个好主意。
function checkBeforeNoon(nextDayDelivery) {
var startTime = '12:00 AM';
var endTime = '12:00 PM';
var curr_time = getval();
if (get24Hr(curr_time) > get24Hr(startTime) && get24Hr(curr_time) < get24Hr(endTime)) {
// before 12pm - next day delivery available
nextDayDelivery = '+1d'; // REMOVE var FROM HERE
} else {
// after 12pm - next day delivery unavailable
nextDayDelivery = '+2d'; // REMOVE var FROM HERE
}
function get24Hr(time) {
var hours = Number(time.match(/^(\d+)/)[1]);
var AMPM = time.match(/\s(.*)$/)[1];
if (AMPM == "PM" && hours < 12) hours = hours + 12;
if (AMPM == "AM" && hours == 12) hours = hours - 12;
var minutes = Number(time.match(/:(\d+)/)[1]);
hours = hours * 100 + minutes;
console.log(time + " - " + hours);
return hours;
}
function getval() {
// ADD MISSING SEMI-COLONS ON THE FOLLOWING 3 LINES
var currentTime = new Date();
var hours = currentTime.getHours();
var minutes = currentTime.getMinutes();
if (minutes < 10) minutes = "0" + minutes;
var suffix = "AM";
if (hours >= 12) {
suffix = "PM";
hours = hours - 12;
}
if (hours == 0) {
hours = 12;
}
var current_time = hours + ":" + minutes + " " + suffix;
return current_time;
}
return nextDayDelivery; // ADD RETURN STATEMENT
}