Python 连接字符串语句放在不同的行上

Question

这是我尝试过但出现错误的方法：

a = 1
b = 2
c = 3
d = 4
e = 5

if(1):
    get = str(a) +","       #Line 1
          +str(b) +","      #Line 2
          +str(c) +","      #Line 3
          +str(d) +","      #Line 4
          +str(e)       #Line 5
else:
    get = ",,,,,"
print(get)

错误：

  File "testingpython.py", line 8
    +str(b) +","      #Line 2
    ^
IndentationError: unexpected indent

然后我尝试删除空格：

a = 1
b = 2
c = 3
d = 4
e = 5

if(1):
    get = str(a) +","       #Line 1
+str(b) +","      #Line 2
+str(c) +","      #Line 3
+str(d) +","      #Line 4
+str(e)       #Line 5
else:
    get = ",,,,,"
print(get)

错误：

  File "testingpython.py", line 12
    else:
       ^
SyntaxError: invalid syntax

请告诉我如何将字符串值分配给位于不同行上的变量。

Answer 1

最简单的解决方案是将括号内的行换行以表明它们属于一起：

if(1):
    get = ( str(a) +","       #Line 1
          +str(b) +","      #Line 2
          +str(c) +","      #Line 3
          +str(d) +","      #Line 4
          +str(e)       #Line 5
    )
else:
    get = ",,,,,"
print(get)

但您可以使用更短的方法：

get = ','.join(str(s) for s in [a, b, c, d, e])

Answer 2

在Python中我们通常使用\符号将单个语句分成多行iff语句不在括号内如：

result = "a" + "b" + "c"

可以表示为：

result = "a" + \
         "b" + \
         "c"

或者如果语句带有括号则不需要 \ as:

result = ("a" + 
          "b" + 
          "c")

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