在 Python 中，如何删除特定字符周围的字符？

Question

我有一个如下所示的列表。在列表的每个项目中，单独的项目由分号分隔，但每个分号周围的 space 数量似乎是随机的：

['New Jersey  ;   46.3% ;  Republican ;         03/10/2015', 'Pennsylvania ; 
      39.0%; Democrat    ;04/30/2012', 'Virginia .   ;54.7% ;Independent 
   ;10/25/10',       'Maryland;44.8%   ;        Democrat; 01/15/16', 'New York;  R50.9%; Republican ;                  09/22/15']

我希望最终输出是一个如下所示的列表：

['New Jersey;46.3%;Republican;03/10/2015', 'Pennsylvania;39.0%;Democrat;04/30/2012', 'Virginia;54.7%;Independent;10/25/10' ... ]

我一直在尝试 .split()，但这并没有删除中间的字符。对 space 和分号的每种可能组合进行 .replace() 是我唯一的希望吗？

Answer 1

使用replace函数：

>>> new_list = [val.replace(' ', '') for val in old_list]

编辑：如前所述，这会删除 "New Jersey" 等词中的空格。相反，使用正则表达式替换：

>>> import re
>>> new_list = [re.sub(' +\.', '', re.sub(' *; *', ';', val)) for val in old_list]
>>> new_list
 ['New Jersey;46.3%;Republican;03/10/2015',
 'Pennsylvania;39.0%;Democrat;04/30/2012',
 'Virginia;54.7%;Independent;10/25/10',
 'Maryland;44.8%;Democrat;01/15/16',
 'New York;R50.9%;Republican;09/22/15']

Answer 2

这里有一个简短的方法。一行就够了

s = ['New Jersey  ;   46.3% ;  Republican ;         03/10/2015', 'Pennsylvania ; 39.0%; Democrat    ;04/30/2012', 'Virginia .   ;54.7% ;Independent ;10/25/10',       'Maryland;44.8%   ;        Democrat; 01/15/16', 'New York;  R50.9%; Republican ;                  09/22/15']

new_list = [';'.join([word.strip() for word in item.split(';')]) for item in s]

这是展开的表格。

new_list = []

for item in s:
    sub_list = [word.strip() for word in item.split(';')]
    new_list.append(';'.join(sub_list))

print(new_list)

输出：

['New Jersey;46.3%;Republican;03/10/2015', 'Pennsylvania;39.0%;Democrat;04/30/2012', 'Virginia .;54.7%;Independent;10/25/10', 'Maryland;44.8%;Democrat;01/15/16', 'New York;R50.9%;Republican;09/22/15']

Answer 3

old_list = ['New Jersey  ;   46.3% ;  Republican ;         03/10/2015', 'Pennsylvania ; 
  39.0%; Democrat    ;04/30/2012', 'Virginia .   ;54.7% ;Independent 
  ;10/25/10',       'Maryland;44.8%   ;        Democrat; 01/15/16', 'New York;    R50.9%; Republican ;                  09/22/15'] 


for row in old_list:
     data = [words.strip() for words in row.split(";")]
     old_list[old_list.index(row)] = ";".join(data)

Answer 4

联合使用re.sub()和replace():

re.sub(r"\s*([;,])\s*",r"",txt).replace(",",", ")

在 Python 中，如何删除特定字符周围的字符？

In Python, how can I remove characters around a specific character?

python

list

strip