检查 csv 是否有空白字段，如果存在空白则写入输出

Question

这是一个 csv 示例：

1- 2018-11-07,hostname-184,IP_INFO, 10.2334.40.334, 255.255.255.0, 
2 - 2018-11-07,hostname-184,IP_INFO, 334.204.334.68, 255.255.255.0,
3- 2018-11-07,hostname,7.1.79-8,IP_INFO, 142.334.89.3342, 255.255.255.0,
4- 2018-11-07,hostname,7.1.80-7,IP_INFO, 13342.221.334.87, 255.255.255.0, 
5- 2018-11-07,hostname-155,IP_INFO, 142.2334.92.212, 255.255.255.0, 
6 - 2018-11-07,hostname-184,IP_INFO, , , 1
7- 2018-11-07,hostname-184,IP_INFO, 10.19334.60.3343, 255.255.255.0,

那么我如何检查最后两个 space 是否为空白（如第 6 行）？

想法是使用这样的东西：

    $contentdnsparsed = Get-Content $destination_RAW_NAS\DNS_NAS_PARSED_0 

For($i=0;$i -lt $contentdnsparsed.count;$i++){
if($contentdnsparsed[$i] -match "running")
    {

 $Global:MatchDNS = $OK } Else {$Global:MatchDNS = $FAIL }

    }

If match "something" in the space 4 and 5 after the "," output = OK else = FAIL.

谢谢大家

Answer 1

尽管您为我们提供了一个 CSV 文件的相当糟糕的示例，但您应该使用 Import-Csv cmdlet。因为 csv 没有 headers，您需要使用 -Header 参数提供它们，如下所示：

$csvContent = Import-Csv -Path "$destination_RAW_NAS\DNS_NAS_PARSED_0" -Header @("Date","HostName", "InfoType","IPAddress","Subnet")
$csvContent | ForEach-Object {
    # test for empty IPAddress fields in the CSV
    if ([string]::IsNullOrEmpty($_.IPAddress)) {
        Write-Host "$($_.HostName) = FAIL" -ForegroundColor Red
        # somewhere in your code you have declared the variables $Global:MatchDNS, $FAIL and $OK I guess..
        $Global:MatchDNS = $FAIL
    }
    else {
        Write-Host "$($_.HostName) = OK" -ForegroundColor Green
        $Global:MatchDNS = $OK
    }
}

希望对您有所帮助

检查 csv 是否有空白字段，如果存在空白则写入输出

check csv for blank fields and write output if exist blank

csv

powershell

parsing

text-parsing

powershell-3.0