Matplotlib - 将标签移动到饼图的中间
Matplotlib - Move labels into middle of pie chart
我的饼图可以正常工作,但我注意到实际图表的文本框似乎无法正常工作。它们只是聚集在一起,所以我想知道有什么办法可以让我将标签移动到白色圆圈所在的中间,并在旁边是否有匹配的颜色?
crimeTypes = dict(crimeData["Crime type"].value_counts())
crimeType = []
totalAmount = []
numberOfCrimes = 14
for key in sorted(crimeTypes, key=crimeTypes.get, reverse=True):
crimeType.append(key)
totalAmount.append(crimeTypes.get(key))
crimeType_sample = crimeType[0:numberOfCrimes]
totalAmount_sample = totalAmount[0:numberOfCrimes]
fig1, ax1 = plt.subplots()
ax1.pie(totalAmount_sample, labels=crimeType_sample, autopct='%1.1f%%', shadow=False, startangle=90)
ax1.axis('equal') # Equal aspect ratio ensures that pie is drawn as a circle.
fig1 = plt.gcf()
fig1.set_size_inches(10,10)
circle = plt.Circle(xy=(0,0), radius=0.75, facecolor='white')
plt.gca().add_artist(circle)
plt.show();
这里有一些示例数据可以重现您的问题:
示例数据:
import pandas as pd
data = (['Burglary']*50 + ['Arson', 'Theft', 'Violence'] + ['Drugs']*10 + ['Other'] +
['Shoplifting']*4 + ['Harassment']*17 + ['Murder', 'Vehicle Crime']*3 +
['Some other Crimes']*12 + ['Even More Crime', 'And Crime', 'And More Crime']*10)
crimeData = pd.DataFrame(data, columns=['Crime type'])
这将导致这个情节:
使用图例
绘图时不要绘制百分比或标签,然后创建一个放在一边的图例:
fig1, ax1 = plt.subplots()
ax1.pie(totalAmount_sample, shadow=False, startangle=90) # No labels or %s
ax1.axis('equal') # Equal aspect ratio ensures that pie is drawn as a circle.
fig1 = plt.gcf()
fig1.set_size_inches(5,5)
circle = plt.Circle(xy=(0,0), radius=0.75, facecolor='white')
plt.gca().add_artist(circle)
plt.legend(labels=[f'{x} {np.round(y/sum(totalAmount_sample)*100,1)}%' for x,y in crimeTypes.items()],
bbox_to_anchor=(1,1))
plt.show();
旋转标签:
创建标签并使用 rotatelabels=True
。尽管在许多情况下这仍然显得局促。
fig1, ax1 = plt.subplots()
labels=[f'{x} {np.round(y/sum(totalAmount_sample)*100,1)}%' for x,y in crimeTypes.items()]
ax1.pie(totalAmount_sample, labels=labels, shadow=False, startangle=90,
rotatelabels=True) # No %
ax1.axis('equal') # Equal aspect ratio ensures that pie is drawn as a circle.
fig1 = plt.gcf()
fig1.set_size_inches(7,7)
circle = plt.Circle(xy=(0,0), radius=0.75, facecolor='white')
plt.gca().add_artist(circle)
plt.show();
我的饼图可以正常工作,但我注意到实际图表的文本框似乎无法正常工作。它们只是聚集在一起,所以我想知道有什么办法可以让我将标签移动到白色圆圈所在的中间,并在旁边是否有匹配的颜色?
crimeTypes = dict(crimeData["Crime type"].value_counts())
crimeType = []
totalAmount = []
numberOfCrimes = 14
for key in sorted(crimeTypes, key=crimeTypes.get, reverse=True):
crimeType.append(key)
totalAmount.append(crimeTypes.get(key))
crimeType_sample = crimeType[0:numberOfCrimes]
totalAmount_sample = totalAmount[0:numberOfCrimes]
fig1, ax1 = plt.subplots()
ax1.pie(totalAmount_sample, labels=crimeType_sample, autopct='%1.1f%%', shadow=False, startangle=90)
ax1.axis('equal') # Equal aspect ratio ensures that pie is drawn as a circle.
fig1 = plt.gcf()
fig1.set_size_inches(10,10)
circle = plt.Circle(xy=(0,0), radius=0.75, facecolor='white')
plt.gca().add_artist(circle)
plt.show();
这里有一些示例数据可以重现您的问题:
示例数据:
import pandas as pd
data = (['Burglary']*50 + ['Arson', 'Theft', 'Violence'] + ['Drugs']*10 + ['Other'] +
['Shoplifting']*4 + ['Harassment']*17 + ['Murder', 'Vehicle Crime']*3 +
['Some other Crimes']*12 + ['Even More Crime', 'And Crime', 'And More Crime']*10)
crimeData = pd.DataFrame(data, columns=['Crime type'])
这将导致这个情节:
使用图例
绘图时不要绘制百分比或标签,然后创建一个放在一边的图例:
fig1, ax1 = plt.subplots()
ax1.pie(totalAmount_sample, shadow=False, startangle=90) # No labels or %s
ax1.axis('equal') # Equal aspect ratio ensures that pie is drawn as a circle.
fig1 = plt.gcf()
fig1.set_size_inches(5,5)
circle = plt.Circle(xy=(0,0), radius=0.75, facecolor='white')
plt.gca().add_artist(circle)
plt.legend(labels=[f'{x} {np.round(y/sum(totalAmount_sample)*100,1)}%' for x,y in crimeTypes.items()],
bbox_to_anchor=(1,1))
plt.show();
旋转标签:
创建标签并使用 rotatelabels=True
。尽管在许多情况下这仍然显得局促。
fig1, ax1 = plt.subplots()
labels=[f'{x} {np.round(y/sum(totalAmount_sample)*100,1)}%' for x,y in crimeTypes.items()]
ax1.pie(totalAmount_sample, labels=labels, shadow=False, startangle=90,
rotatelabels=True) # No %
ax1.axis('equal') # Equal aspect ratio ensures that pie is drawn as a circle.
fig1 = plt.gcf()
fig1.set_size_inches(7,7)
circle = plt.Circle(xy=(0,0), radius=0.75, facecolor='white')
plt.gca().add_artist(circle)
plt.show();