当应用程序处于后台状态 React native 时深度链接不起作用

Question

我正在创建基于 React 的电子商务应用程序 native.here 我需要从 url 打开单个产品页面 shared.actually 当应用程序处于终止状态时它会工作，但如果应用程序处于 background/inactive 状态，它不会工作。在 background/inactive state.I 上打开时共享 url 变为空已附上我的代码。

// following code working for app killing state

componentWillMount() {

    if (Platform.OS === 'android') {
      console.log("Testing");debugger

      //Constants.OneTimeFlag == false;
          Linking.getInitialURL().then(url => {
            console.log(url);
            var str = url
            var name = str.split('/')[4]
            Constants.isLinking = true;
           this.setState({ shop_Id: name})


           if (str)
           {
            this.setState({ isFromHomeLinking:'FROM_LINK' })
            this.props.navigation.navigate('SingleProductScreen', { ListViewClickItemHolder: [this.state.shop_Id,1,this.state.isFromHomeLinking] });

           }


          });

    }

    else {
        Linking.addEventListener('url', this.handleNavigation);
      }

  }

Not working code following..



componentDidMount() {
    AppState.addEventListener('change', this._handleAppStateChange);
}

componentWillUnmount() {
    AppState.removeEventListener('change', this._handleAppStateChange);
  }

this.state.appState declared in constructor(props)

_handleAppStateChange = (nextAppState) => {
    if (this.state.appState.match(/inactive|background/) && nextAppState === 'active') {
     console.log('App has come to the foreground!');debugger
 if (Platform.OS === 'android') {
          console.log("Testing");debugger

          //Constants.OneTimeFlag == false;
              Linking.getInitialURL().then(url => {
                console.log(url);
                var str = url
                var name = str.split('/')[4]
                Constants.isLinking = true;
               this.setState({ shop_Id: name})


               if (str)
               {
                this.setState({ isFromHomeLinking:'FROM_LINK' })
                this.props.navigation.navigate('SingleProductScreen', { ListViewClickItemHolder: [this.state.shop_Id,1,this.state.isFromHomeLinking] });

               }


              });

        }

        else {
            Linking.addEventListener('url', this.handleNavigation);
          }
    }
    }

当我在后台状态下从 whatsapp 和应用程序打开外部 link 时 Linking.getInitialURL() 接收为 null ..

我在清单文件中有以下内容

<activity
        android:name=".MainActivity"
        android:label="@string/app_name"
        android:configChanges="keyboard|keyboardHidden|orientation|screenSize"
        android:windowSoftInputMode="adjustResize"
        android:launchMode="singleTask">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
        <intent-filter>
 <action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
 <category android:name="android.intent.category.BROWSABLE" />
<data android:scheme="http"
 android:host="demo1.zgroo.com" />
</intent-filter>
      </activity>

以下是我的样本URL..

http://demo1.zgroo.com/xxxx

请告诉我任何解决方案..

提前致谢..

Answer 1

您需要为此案例注册链接侦听器。

componentDidMount() {
  Linking.addEventListener('url', this._handleOpenURL);
},
componentWillUnmount() {
  Linking.removeEventListener('url', this._handleOpenURL);
},
_handleOpenURL(event) {
  console.log(event.url);
}

更多https://facebook.github.io/react-native/docs/linking

Answer 2

这是 Anurag 使用挂钩的答案的一个版本：

export function useDeepLinkURL() {
  const [linkedURL, setLinkedURL] = useState<string | null>(null);

  // 1. If the app is not already open, it is opened and the url is passed in as the initialURL
  // You can handle these events with Linking.getInitialURL(url) -- it returns a Promise that
  // resolves to the url, if there is one.
  useEffect(() => {
    const getUrlAsync = async () => {
      // Get the deep link used to open the app
      const initialUrl = await Linking.getInitialURL();
      setLinkedURL(decodeURI(initialUrl));
    };

    getUrlAsync();
  }, []);

  // 2. If the app is already open, the app is foregrounded and a Linking event is fired
  // You can handle these events with Linking.addEventListener(url, callback)
  useEffect(() => {
    const callback = ({url}: {url: string}) => setLinkedURL(decodeURI(url));
    Linking.addEventListener('url', callback);
    return () => {
      Linking.removeEventListener('url', callback);
    };
  }, []);

  const resetURL = () => setLinkedURL(null);

  return {linkedURL, resetURL};
}

然后您可以将其用于：

const {linkedURL, resetURL} = useDeepLinkURL();

useEffect(() => {
    // ... handle deep link
    resetURL();
}, [linkedURL, resetURL])

我添加了函数 resetURL，因为如果用户与该应用程序共享同一个文件两次，您会想要加载它两次。但是，因为深度 link 最终会相同，所以 useEffect 不会再次被触发。您可以通过将 linkedURL 设置为空来使其再次触发，因此下次共享文件时，您可以确定它会导致 useEffect 变为运行。

此外，我使用decodeURI解码传入的URL，因为如果你使用像react-native-fs这样的库从指定路径加载文件，它不会除非您使用 decodeURI.

，否则能够处理名称中带有空格的文件

Answer 3

从 componentwillunmount 中删除侦听器。无需在componentwillunmount中编写任何代码，因为链接的addListener将始终监听，然后只有当您从后台（通过单击新的深层链接）进入活动状态时才会触发。

当应用程序处于后台状态 React native 时深度链接不起作用

Deep linking not working when app is in background state React native

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