使用 Mockery 测试 Laravel View Composer

Question

我正在尝试测试我的 View Composer。每当我将对象传递给 $view->with('string', $object) 时，我的测试都会失败。这是我像这样进行测试的时候：

$view
    ->shouldReceive('with')
    ->with('favorites', $this->user->favorites(Ad::class)->get())
    ->once();

我很确定这是由于严格的检查。所以我环顾四周，看到了this issue。但是，我似乎无法让它工作。闭包 return 为真，但测试失败：

Mockery\Exception\InvalidCountException : Method with('favorites', < Closure===true >) from Mockery_3_Illuminate_View_View should be called exactly 1 times but called 0 times.

这是我目前的测试

public function it_passes_favorites_to_the_view()
{
    $this->setUpUser(); // basically sets $this->user to a User object

    Auth::shouldReceive('user')
        ->once()
        ->andReturn($this->user);

    $composer = new FavoritesComposer();

    $view = Mockery::spy(View::class);

    $view
        ->shouldReceive('with')
        ->with('favorites', Mockery::on(function($arg) {
            $this->assertEquals($this->user->favorites(Ad::class)->get(), $arg);
        }))
        ->once();

    $composer->compose($view);
}

FavoritesComposer class:

public function compose(View $view)
{
    $user = Auth::user();

    $favorites = $user 
        ? $user->favorites(Ad::class)->get()
        : collect([]);

    $view->with('favorites', $favorites);
}

如何测试这样的对象？

Answer 1

我通过用 $view->with(['favorites' => $favorites]); 替换 $view->with('favorites', $favorites); 解决了这个问题，然后像这样测试它：

$view
    ->shouldReceive('with')
    ->with(['favorites' => $this->user->favorites(Ad::class)->get()])
    ->once();

所以，基本上只使用 with() 方法中的一个参数就是为我修复它的方法。

使用 Mockery 测试 Laravel View Composer

Testing Laravel View Composers with Mockery

laravel

mockery