Tkinter Optionmenu StringVar.get() 返回空白

Question

我正在创建一个带有 'for loop' 的 Tkinter window，这样它可以在以后我决定添加更多问题时进行自我调整。我的问题是我无法在选项菜单上保存输入的值。到目前为止，我得到的只是 list1 = ['', '', ''] 而 Strg_var = [StringVar, StringVar, StringVar] 并且它只打印空白和变量 PY_numbers.

import tkinter as tk
from tkinter import *

LARGE_FONT = ("Arial", 12)

window=Tk()

def _save():
    print(*list1, sep = ", ")
    print(*Strg_var, sep = ", ")

Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]          
choices = ['-', 'Yes', 'No'] 
n = 0
Strg_var=[0]*len(Questionlist)
list1=[]
for n in range(len(Questionlist)): 
    Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
    a = tk.StringVar(window)
    OptionMenu(window, a, choices[0], *choices).grid(row = n, column=2, padx=10, sticky="WE")
    list1.append(a.get())

tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")

window.mainloop()

有人可以帮助我解决如何将选项菜单用户选择保存到列表或任何其他方式的问题吗？

Answer 1

您可以列出 StringVar（初始化它们，我的代码中没有这样做）。每次选择一个选项时，相应的项目都会改变。所以我会这样做。

import tkinter as tk

LARGE_FONT = ("Arial", 12)

window=tk.Tk()

def _save():
    print(list(map(lambda x: x.get(), a)))

Questionlist = ["A. Is A true? :", "B. Is B true? :", "C. Is C true? :"]          
choices = ['-', 'Yes', 'No']
a = [tk.StringVar(window) for i in range(len(Questionlist))]
n = 0
for n in range(len(Questionlist)): 
    tk.Label(window, text=Questionlist[n], font = LARGE_FONT, background = "white").grid(row= n, column=0, columnspan=2, padx=10, pady = 10, sticky="W")
    Strg_var = tk.StringVar(window)
    tk.OptionMenu(window, a[n], *choices).grid(row = n, column=2, padx=10, sticky="WE")

tk.Button(window, text="Save", command = _save,width=18).grid(row=16, column=0, padx=10, pady=15, sticky="W")

window.mainloop()

输出：

['No', '-', 'Yes']

Tkinter Optionmenu StringVar.get() 返回空白

Tkinter Optionmenu StringVar.get() returning blank

python

tkinter

optionmenu