javascript 混合中的构造函数和 class 属性

Question

我正在尝试理解 javascript 中的 mixin，我目前阅读的所有示例和文章都在谈论添加方法而不是属性。

我找到了Alex Jover Morales' article really useful and i have slightly modified his example to include an additional mixin and constructors with new properties within the mixins here。

我在下面所做的是反模式吗？在 mixin 中使用构造函数和属性有问题吗？在每个 mixin 的构造函数中调用 super() 是否有问题？

const PlayMixin = superclass => class extends superclass {

  constructor(args) {
    let { favouriteGame } = args        
    super(args);
    this.favouriteGame=favouriteGame;
  }

  play() {
    console.log(`${this.name} is playing ${this.favouriteGame}`);
  }
};


const FoodMixin = superclass => class extends superclass {

  constructor(args) {
    let { genericFood } = args        
    super(args);
    this.genericFood=genericFood;
  }

  eat() {
    console.log(`${this.name} is eating ${this.genericFood}`);
  }

  poop() {
    console.log("Going to ");
  }
};


class Animal {
  constructor(args) {
    let {name} = args
    this.name = name
  }
}

class Dog extends PlayMixin(FoodMixin(Animal)) {
  constructor(...args) {    
    super(...args)
}

  bark() {
    console.log("Woff woff!")
  }

  haveLunch() {
    this.eat();
    this.poop();
  }
}

const jack = new Dog({name:"Jack", genericFood:"lobster", 
favouriteGame:"chess"});
jack.haveLunch();
jack.play();

.as-console-wrapper { max-height: 100%!important; top: 0; }

Answer 1

Is what i have done below an anti-pattern?

不，不是。

Is there a problem with having a constructor and properties within a mixin?

不，只要您调用 super(...) 的方式适用于 classes 中的所有混合。

Is there a problem with calling super() within each mixin's contructor?

没有，super总是指向扩展的class，调用那个构造函数没有问题。

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