TableView 中的搜索栏无法调用数组

Question

我无法从 Json 调用数组，我得到两点错误。

Can not assign a value of type '[CoinModel]' to type '[String]'

Can not assign value of type 'CoinModel' to type 'String?'

我哪里出错了？

import UIKit
import Alamofire
import SwiftyJSON


class ViewController: UIViewController, UITableViewDataSource, UITableViewDelegate, UISearchBarDelegate {

@IBOutlet weak var tableView: UITableView!
@IBOutlet weak var searchBar: UISearchBar!

let URL_DATA = "https://api.coincap.io/v2/assets"

var coin = [CoinModel]()
var searchCoin = [String]()
var searching = false

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {

    if searching {
        return searchCoin.count
    } else {
        return coin.count
    }

}


func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as! CoinTableViewCell


    tableView.backgroundColor = .clear
    cell.backgroundColor = .clear


    if searching{
        cell.nameLabel.text = searchCoin[indexPath.row]
    } else {
        cell.nameLabel.text = coin[indexPath.row]
    }


    let coindata: CoinModel
    coindata = coin[indexPath.row]


    cell.nameLabel.text = coindata.name
    cell.symbolLabel.text = coindata.symbol
    let priceFloat = (coindata.price as NSString).floatValue
    let costString = String(format:"%.3f", priceFloat)
    cell.priceLabel.text = "\(costString)"
    let percentFloat = (coindata.percent as NSString).floatValue
    let percentString = String(format:"%.2f", percentFloat)

    if percentFloat < 0 {
        cell.percentLabel.text = "\(percentString)%"
        cell.percentLabel.textColor = UIColor(hexString: "#F47E99")
    } else {
         cell.percentLabel.text = "+\(percentString)%"
         cell.percentLabel.textColor = UIColor(hexString: "#19984A")
    }




    return cell

}

func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {

    searchCoin =  coin.filter({[=10=].name.prefix(searchText.count) == searchText})
    searching = true
    tableView.reloadData()
}

func getCoinData() {
    Alamofire.request(URL_DATA).responseJSON { response in

        if let json = response.result.value as? [String: Any], let arr = json["data"] as? [[String: Any]] {
            let CoinArray: [[String: Any]] = arr

            for dict in CoinArray {
                if let name = dict["name"] as? String,
                    let symbol = dict["symbol"] as? String,
                    let price = dict["priceUsd"] as? String,
                    let percent = dict["changePercent24Hr"] as? String

                {

                    let coinnModal: CoinModel = CoinModel(name: name, symbol: symbol, price: price, percent: percent)
                    self.coin.append(coinnModal)


                }

                self.tableView.reloadData()
            }

        }
    }
}



override func viewDidLoad() {
    super.viewDidLoad()
    getCoinData()

 }


}

我在 cell.nameLabel.text = coin[indexPath.row]

上出错

Cannot assign value of type 'CoinModel' to type 'String?'

还有 searchCoin = coin.filter({[=13=].name.prefix(searchText.count) == searchText})

Cannot assign value of type '[CoinModel]' to type '[String]'

型号：

import Foundation

class CoinModel {

var name: String
var symbol: String
var price: String
var percent: String

init(name: String, symbol: String, price: String, percent: String) {

    self.name = name
    self.symbol = symbol
    self.price = price
    self.percent = percent
 }


}

Answer 1

您似乎想将 CoinModel 的名称分配给标签。

cell.nameLabel.text = coin[indexPath.row].name

对于映射，如果您想要 CoinModel 个名称的数组，那么您应该映射过滤后的结果。

searchCoin = coin.compactMap( {[=11=].name.prefix(searchText.count) == searchText ? [=11=].name: nil} )

提示：您应该使用专有名称来描述您的变量。例如，您有一个 CoinModel 的数组，您将其命名为 coin，而实际上可以将其命名为 coins。另外，我建议您在存储数据源时保持一致性。一个数据源是 CoinModel 的数组，而另一个是 String 的数组。你应该只有一个，最好是 CoinModel imo.

TableView 中的搜索栏无法调用数组

Searchbar in TableView cant call array

ios

swift

uitableview

uisearchbar