正则表达式：如何将字符串作为唯一的有序模式获取？
Regex: How to get string as only ordered pattern?
我有这个字符串：
"You to You know to You have to know Regex more You have to know everything of Regex"
我想得到模式的结果：（你）（到）（正则表达式）。
即：
"You to You know to (You) have (to) know (Regex) more (You) have (to) know everything of (Regex)"
但是我的正则表达式得到了这个：
"(You) (to) You know to You have to know (Regex) more (You) have (to) know everything of (Regex)"
正则表达式：(You).+?(?=to)(to).+?(?=Regex)(Regex)
我知道我的 Regex 工作正常，但我不知道如何跳过 First 'You'。
谢谢。
您正在寻找：
(?i)(you)(?:(?!you).)*(to)(?:(?!to).)*(regex)
可以找到解释和演示HERE。
我有这个字符串：
"You to You know to You have to know Regex more You have to know everything of Regex"
我想得到模式的结果：（你）（到）（正则表达式）。 即：
"You to You know to (You) have (to) know (Regex) more (You) have (to) know everything of (Regex)"
但是我的正则表达式得到了这个：
"(You) (to) You know to You have to know (Regex) more (You) have (to) know everything of (Regex)"
正则表达式：(You).+?(?=to)(to).+?(?=Regex)(Regex)
我知道我的 Regex 工作正常，但我不知道如何跳过 First 'You'。
谢谢。
您正在寻找：
(?i)(you)(?:(?!you).)*(to)(?:(?!to).)*(regex)
可以找到解释和演示HERE。