将 2 个黄瓜 JSON 报告与 ruby 进行比较

Question

问题是：我有2份JSON格式的黄瓜测试报告我需要从这些报告中删除多余的键值对并进行比较，但我无法理解如何从这 2 个 json 中删除不必要的数据，因为它们在 JSON.parse 之后的结构（具有许多嵌套 [ 的数组或散列） =15=]).如果有一些宝石或已知的解决方案可以做到这一点，请提出建议 JSON 结构例如:

[
  {
    "uri": "features/home_screen.feature",
    "id": "as-a-user-i-want-to-explore-home-screen",
    "keyword": "Feature",
    "name": "As a user I want to explore home screen",
    "description": "",
    "line": 2,
    "tags": [
      {
        "name": "@home_screen",
        "line": 1
      }
    ],
    "elements": [
      {
        "keyword": "Background",
        "name": "",
        "description": "",
        "line": 3,
        "type": "background",
        "before": [
          {
            "match": {
              "location": "features/step_definitions/support/hooks.rb:1"
            },
            "result": {
              "status": "passed",
              "duration": 505329000
            }
          }
        ],
        "steps": [
          {
            "keyword": "Given ",
            "name": "I click OK button in popup",
            "line": 4,
            "match": {
              "location": "features/step_definitions/registration_steps.rb:91"
            },
            "result": {
              "status": "passed",
              "duration": 2329140000
            }
          },
          {
            "keyword": "And ",
            "name": "I click Allow button in popup",
            "line": 5,
            "match": {
              "location": "features/step_definitions/registration_steps.rb:96"
            },
            "result": {
              "status": "passed",
              "duration": 1861776000
            }
          }
        ]
      },

Answer 1

既然你要的是 gem，你可以试试 iteraptor 我专门为这类任务创建的。

它允许迭代、映射和减少深层嵌套结构。例如，要在所有级别上过滤掉所有名为 "name" 的键，您可以这样做：

input.iteraptor.reject(/name/)

可以在上面链接的 github 页面上找到更详细的说明。

将 2 个黄瓜 JSON 报告与 ruby 进行比较

Compare 2 cucumber JSON reports with ruby

ruby

json

cucumber