即使缺少必填字段，Rapidjson 也能验证成功

Question

我原以为 rapidjson 会给出验证错误，因为我的 json 文件不包含架构中提到的 'required' 字段之一。但是，由于某些原因，这不会发生。

dbconf.json（json 文件）

{
        "MAX_CONNECTION_PER_HOST":20,
        "QUEUE_IO_SIZE":10485,
        "Garbage":50000
}

这是测试代码和架构。

#include "rapidjson/document.h"
#include "rapidjson/error/en.h"
#include "rapidjson/schema.h"
#include <rapidjson/stringbuffer.h>
#include<iostream>
#include<string>
#include<fstream>

using namespace std;

const char g_plJsonSchema[]="{\
                             \"$schema\": \"http://json-schema.org/draft-04/schema#\",\
                             \"title\": \"Schema\",\
                             \"description\": \"JSON schema for validating Json file\",\
                             \"type\": \"object\",\
                             \"properties\": {\
                             \"MAX_CONNECTION_PER_HOST\": { \"type\": \"number\" },\
                              \"QUEUE_IO_SIZE\": { \"type\": \"number\" },\
                              \"REQUEST_LOW_WATER_MARK\": { \"type\": \"number\" },\
\"required\": [\
\"MAX_CONNECTION_PER_HOST\",\
\"QUEUE_IO_SIZE\",\
\"REQUEST_LOW_WATER_MARK\"\
]\
      }\
}";

int main()

{
        rapidjson::Document l_peerAddSchemaDoc, l_peerAddDataDoc;
        l_peerAddSchemaDoc.Parse(g_plJsonSchema);
        if(l_peerAddSchemaDoc.HasParseError())
        {
                printf("JSON schema file is not a valid JSON file\n");
                return -1;
        }
        std::ifstream l_confDataIStream("dbconf.json");
        std::string l_confDataIStreamStr((std::istreambuf_iterator<char>(l_confDataIStream)),(std::istreambuf_iterator<char>()));
        l_peerAddDataDoc.Parse(l_confDataIStreamStr.c_str());


        rapidjson::SchemaDocument l_schemaDocument(l_peerAddSchemaDoc);
        rapidjson::SchemaValidator l_SchemaValidator(l_schemaDocument);

        if(!l_peerAddDataDoc.Accept(l_SchemaValidator))
        {
                rapidjson::StringBuffer sb;
                l_SchemaValidator.GetInvalidSchemaPointer().StringifyUriFragment(sb);
                printf("Invalid schema: %s\n", sb.GetString());
                printf("Invalid keyword: %s\n", l_SchemaValidator.GetInvalidSchemaKeyword());
                sb.Clear();
                l_SchemaValidator.GetInvalidDocumentPointer().StringifyUriFragment(sb);
                printf("Invalid document: %s\n", sb.GetString());
        }
else
printf("\nJson file validated with the given schema successfully\n");

        return 0;
}

我得到以下输出

Json file validated with the given schema successfully

Answer 1

您的问题是 required 应该在根级别，而不是在 properties 内部。事实上，您当前的模式无效，因为 properties 中的所有键值都应该只是对象。

{
  "$schema": "json-schema.org/draft-04/schema#",
  "title": "Schema",
  "description": "JSON schema for validating Json file",
  "type": "object",
  "properties": {
    "MAX_CONNECTION_PER_HOST": {
      "type": "number"
    },
    "QUEUE_IO_SIZE": {
      "type": "number"
    },
    "REQUEST_LOW_WATER_MARK": {
      "type": "number"
    }
  },
  "required": [
      "MAX_CONNECTION_PER_HOST",
      "QUEUE_IO_SIZE",
      "REQUEST_LOW_WATER_MARK"
    ]
}

我使用 https://www.jsonschemavalidator.net 验证了针对实例的模式进行测试。

即使缺少必填字段，Rapidjson 也能验证成功

Rapidjson giving validation success even when required field is missing

jsonschema

rapidjson