Bash 脚本将 csv 保存在数组中并搜索字符串的一部分

Question

编辑我的脚本后，我想很快解释一下我想做什么：

检查文件夹中是否有文件
查看文件名的开头
搜索不到 1 小时的文件
获取文件并执行 sqlldr ..如果成功将文件移动到其他文件夹...如果没有发送邮件

这是我的脚本，有人可以告诉我这是否可行吗？我不确定语法，也不确定 nr. 3和4.发送邮件是这样的

    #!/bin/sh

    #check if files are in folder
    declare -a arrCSV   #create array
    for file in *.csv
    do
    arrCSV=("${CSV[@]}" "$file")
    done

    shopt -s nullglob
    for file in read*.csv; do
    #run on all files starting with "read" and ending with ".csv" 
  for find $LOCATION -name $file -type f -mmin -60 do
    if
    sqlldr read*.csv 
then mv "$file" "$HOME/fail/" ;
else{ echo "Failed to load" | mail -s "FAIL" email@email.com}
done
    done

    for file in write*.csv; do
    #run on all files starting with "write" and ending with ".csv" 
      for find $LOCATION -name $file -type f -mmin -60 do
 if
sqlldr write*.csv 
then mv "$filen" "$HOME/unisem/fail/" ;
else { echo "Failed to load 2" | mail -s "FAIL" email@email.com}
done
    done

Answer 1

如果可以按任何顺序处理读...和写...文件，则不需要数组：

shopt -s nullglob
for file in read*.csv; do
    # run on all files starting with "read" and ending with ".csv" 
    sqldr ...
done
for file in write*.csv; do
    # run on all files starting with "write" and ending with ".csv" 
    sqldr ...
done

Bash 脚本将 csv 保存在数组中并搜索字符串的一部分

Bash script save csv in array and search for part of string

unix

bash

shell

sh

subshell