QueryDSL GroupBy 和 Sum

QueryDSL GroupBy and Sum

我有这些 QueryDSL 语句:

BooleanExpression alwaysTrueExpression = match(null, null, datePeriod, period);

if (minAmount != null) {
    alwaysTrueExpression = alwaysTrueExpression.and(aggregatedOrder.totalUnitAmountWithoutTax.sum().goe(minAmount));
}
if (maxAmount != null) {
    alwaysTrueExpression = alwaysTrueExpression.and(aggregatedOrder.totalUnitAmountWithoutTax.sum().loe(maxAmount));
}

JPAQuery<AggregatedOrder> query = selectFrom(aggregatedOrder);
query = query.where(alwaysTrueExpression);
log.debug("sql={}", query);

return query.transform(GroupBy.groupBy(aggregatedOrder.tradingPromoterBranch.promoter).as(GroupBy.sum(aggregatedOrder.totalUnitAmountWithoutTax)));

但它抛出错误:

Caused by: org.postgresql.util.PSQLException: ERROR: aggregate functions are not allowed in WHERE

我想按发起人对 aggregatedOrder 进行分组并使用金额进行过滤。

我认为您混合了 Querydsl 支持的两种类型的分组:

  • query.transform(...):一旦从数据库中获取数据,组就会在内存中产生结果。在这种情况下,查询不包含 "group by" 子句,数据转换在 "java side" 上执行。
  • query.groupBy(...):将 group by 子句添加到您的查询中。在这种情况下,分组由数据库执行。

如果您在查询中需要聚合函数,则需要使用 "query.groupBy(...)".

提供 "group by" 列

以下是我聚合列并按总和筛选的方法:

BooleanExpression alwaysTrueExpression = Expressions.asBoolean(true).isTrue();

NumberExpression<BigDecimal> totalUnitAmountWithoutTax = aggregatedOrder.totalUnitAmountWithoutTax.sum();
NumberExpression<Integer> totalQuantity = aggregatedOrder.quantity.sum();
NumberPath<Long> qPromoter = aggregatedOrder.tradingPromoterBranch.promoter.id;

BooleanExpression amountExpression = Expressions.asBoolean(true).isTrue();
if (minAmount != null) {
    amountExpression = amountExpression.and(totalUnitAmountWithoutTax.goe(minAmount));
}
if (maxAmount != null) {
    amountExpression = amountExpression.and(totalUnitAmountWithoutTax.loe(maxAmount));
}

JPAQuery<Tuple> query = jpaQueryFactory.select(qPromoter, totalUnitAmountWithoutTax, totalQuantity).from(aggregatedOrder).groupBy(qPromoter);
query = query.where(alwaysTrueExpression).having(amountExpression);

return query.fetch();