QMap 值作为结构
QMap values as structs
假设我们有这个样本:
struct test
{
QString name;
int count = 0;
};
QMap<QString,test> map;
test test1;
test1.name = "doc1";
map.insertMulti("pen",test1);
test test2;
test2.name = "doc2";
map.insertMulti("pen",test2);
if(map.contains("pen"))
{
map.value("pen",test1).count++; // Here goes the error
//map["pen"].count++; //works but increments count of last inserted struct
}
foreach (test value, map) {
qDebug() << value.name << " " << value.count;
}
所以我要做的是检查密钥是否已经存在,然后增加我需要的结构的数量。
请告知如何正确执行此操作。
value()
returns a constant value that can not be modified, instead You must use an iterator using the find()
方法:
struct Test{
QString name;
int count = 0;
};
QMultiMap<QString, Test> map;
Test test;
test.name = "doc1";
map.insert("pen", test);
if(map.contains("pen")){
qDebug() << "before: " << map.value("pen").count;
QMultiMap<QString, Test>::iterator it = map.find("pen");
it->count += 10;
qDebug() << "after: " << map.value("pen").count;
}
输出:
before: 0
after: 10
更新:
在 QMap 的情况下,你必须使用 operator [] 即 returns 存储值的引用:
struct Test{
QString name;
int count = 0;
};
QMap<QString, Test> map;
Test test1;
test1.name = "doc1";
map.insertMulti("pen",test1);
Test test2;
test2.name = "doc2";
map.insertMulti("pen", test2);
if(map.contains("pen")){
qDebug() << "before: " << map.value("pen").count;
map["pen"].count++;
qDebug() << "after: " << map.value("pen").count;
}
输出:
before: 0
after: 1
更新:
您必须使用 find() 来获取具有该键的第一个元素的迭代器,如果您想访问具有相同键的元素,您必须增加迭代器。
struct Test{
QString name;
int count = 0;
};
QMap<QString, Test> map;
Test test1;
test1.name = "doc1";
map.insertMulti("pen",test1);
Test test2;
test2.name = "doc2";
map.insertMulti("pen", test2);
if(map.contains("pen")){
// get the first item with the key
QMap<QString, Test>::iterator it = map.find("pen");
// the next element
it++;
// update value
it->count++;
}
for(const Test & value: map){
qDebug() << value.name << " " << value.count;
}
输出:
"doc2" 0
"doc1" 1
假设我们有这个样本:
struct test
{
QString name;
int count = 0;
};
QMap<QString,test> map;
test test1;
test1.name = "doc1";
map.insertMulti("pen",test1);
test test2;
test2.name = "doc2";
map.insertMulti("pen",test2);
if(map.contains("pen"))
{
map.value("pen",test1).count++; // Here goes the error
//map["pen"].count++; //works but increments count of last inserted struct
}
foreach (test value, map) {
qDebug() << value.name << " " << value.count;
}
所以我要做的是检查密钥是否已经存在,然后增加我需要的结构的数量。
请告知如何正确执行此操作。
value()
returns a constant value that can not be modified, instead You must use an iterator using the find()
方法:
struct Test{
QString name;
int count = 0;
};
QMultiMap<QString, Test> map;
Test test;
test.name = "doc1";
map.insert("pen", test);
if(map.contains("pen")){
qDebug() << "before: " << map.value("pen").count;
QMultiMap<QString, Test>::iterator it = map.find("pen");
it->count += 10;
qDebug() << "after: " << map.value("pen").count;
}
输出:
before: 0
after: 10
更新:
在 QMap 的情况下,你必须使用 operator [] 即 returns 存储值的引用:
struct Test{
QString name;
int count = 0;
};
QMap<QString, Test> map;
Test test1;
test1.name = "doc1";
map.insertMulti("pen",test1);
Test test2;
test2.name = "doc2";
map.insertMulti("pen", test2);
if(map.contains("pen")){
qDebug() << "before: " << map.value("pen").count;
map["pen"].count++;
qDebug() << "after: " << map.value("pen").count;
}
输出:
before: 0
after: 1
更新:
您必须使用 find() 来获取具有该键的第一个元素的迭代器,如果您想访问具有相同键的元素,您必须增加迭代器。
struct Test{
QString name;
int count = 0;
};
QMap<QString, Test> map;
Test test1;
test1.name = "doc1";
map.insertMulti("pen",test1);
Test test2;
test2.name = "doc2";
map.insertMulti("pen", test2);
if(map.contains("pen")){
// get the first item with the key
QMap<QString, Test>::iterator it = map.find("pen");
// the next element
it++;
// update value
it->count++;
}
for(const Test & value: map){
qDebug() << value.name << " " << value.count;
}
输出:
"doc2" 0
"doc1" 1