Django，URL 和未找到视图

Question

我正在使用 Django 2.1 并测试 views.py 和 urls.py 我不明白的是为什么每当我输入 URL http://127.0.0.1:8000/blog/post_list 我都会收到 404 错误消息

我的顶urls.py:

from django.urls import path
from django.contrib import admin
from django.conf.urls import include, url
from organizer import urls as organizer_urls
from blog import urls as blog_urls

urlpatterns = [
    path('admin/', admin.site.urls),
    path('', include(organizer_urls)),
    path('tag/', include(organizer_urls)),
    path('startup/', include(organizer_urls)),
    path('blog/', include(blog_urls))
]

我的应用程序的 urls.py

from django.urls import path
from blog.views import post_list, post_detail

urlpatterns = [
    path('',
        post_list,
        name='blog_post_list'),
    path(
        '<int:year>/<int:month>/<slug:slug>',
        post_detail,
        name='blog_post_detail'),
]

我的应用程序的 views.py:

from django.shortcuts import render, get_object_or_404
from .models import Post
# Create your views here.

def post_list(request):
    return render(
        request,
        'blog/post_list.html',
        {'post_list':Post.object.all()}
    )

def post_detail(request, year, month, slug):
    post = get_object_or_404(
        Post,
        pub_date__year=year,
        pub_date__month=month,
        slug=slug)
    return render(
        request,
        'blog/post_detail.html',
        {'post': post})

错误信息是：

Using the URLconf defined in suorganizer_project.urls, Django tried these URL patterns, in this order:

admin/ tag/tag_list [name='organizer_tag_list'] tag// startup/startup_list [name='organizer_startup_list'] startup// [name='organizer_startup_detail'] tag/ startup/ blog/ The empty path didn't match any of these.

为什么？ url 在那里：

path('',
        post_list,
        name='blog_post_list'),

这会带我到 post_list 观看次数：

def post_list(request):
    return render(
        request,
        'blog/post_list.html',
        {'post_list':Post.object.all()}
    )

和 returns 对 post 中所有对象的查询 --Post.object.all()-- ?

我不明白我错过了什么，非常感谢您的帮助！ :)

Answer 1

post_list 不在您的 URL 模式中，但它是您的函数名称。如果您以这种方式访问 URL：127.0.0.1:8000/blog/ 它将起作用并根据此模式调用 post_list() 视图

path('',
    post_list,
    name='blog_post_list'),

如果您想让 URL 正常工作，只需按以下方式编辑您的模式，添加 post_list 字符串。

path('post_list',
    post_list,
    name='blog_post_list'),

Django，URL 和未找到视图

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