无法将固定宽度的文件转换为 csv

Trouble converting a fixed-width file into a csv

抱歉,如果这是一个新手问题,但我没有在 Whosebug 上找到这个特定问题的答案。 我有一个(非常大的)固定宽度的数据文件,如下所示: simplefile.txt

ratno      fdate ratname                        typecode country        
12346 31/12/2010 HARTZ                              4    UNITED STATES
12444 31/12/2010 CHRISTIE                           5    UNITED STATES
12527 31/12/2010 HILL AIR                           4    UNITED STATES
15000 31/12/2010 TOKUGAVA  INC.                     5    JAPAN
37700 31/12/2010 HARTLAND                           1    UNITED KINGDOM
37700 31/12/2010 WILDER                             1    UNITED STATES  
18935 31/12/2010 FLOWERS FINAL SERVICES INC         5    UNITED STATES
37700 31/12/2010 MAPLE CORPORATION                  1    CANADA
48614 31/12/2010 SERIAL MGMT  L.P.                  5    UNITED STATES
 1373 31/12/2010 AMORE MGMT GROUP N A               1    UNITED STATES

我正在尝试使用终端将其转换为 csv 文件(该文件对于 Excel 而言太大),如下所示:

ratno,fdate,ratname,typecode,country        
12346,31/12/2010,HARTZ,4,UNITED STATES
12444,31/12/2010,CHRISTIE,5,UNITED STATES
12527,31/12/2010,HILL AIR,4,UNITED STATES
15000,31/12/2010,TOKUGAVA  INC.,5,JAPAN
37700,31/12/2010,HARTLAND,1,UNITED KINGDOM
37700,31/12/2010,WILDER,1,UNITED STATES 
18935,31/12/2010,FLOWERS FINAL SERVICES INC,5,UNITED STATES
37700,31/12/2010,MAPLE CORPORATION,1,CANADA
48614,31/12/2010,SERIAL MGMT  L.P.,5,UNITED STATES
 1373,31/12/2010,AMORE MGMT GROUP N A,1,UNITED STATES

我在这个网站上搜索了一下,找到了一个可能的解决方案,该解决方案依赖于 awk shell 命令:

awk -v FIELDWIDTHS="5 11 31 9 16" -v OFS=',' '{=;print}'   "simpletestfile.txt"

但是,当我在终端中执行上述命令时,它无意中还在所有空格中插入了逗号,在应该保留为单个字段的单独单词中。以上执行结果如下:

ratno,fdate,ratname,typecode,country
12346,31/12/2010,HARTZ,4,UNITED,STATES
12444,31/12/2010,CHRISTIE,5,UNITED,STATES
12527,31/12/2010,HILL,AIR,4,UNITED,STATES
15000,31/12/2010,TOKUGAVA,INC.,5,JAPAN
37700,31/12/2010,HARTLAND,1,UNITED,KINGDOM
37700,31/12/2010,WILDER,1,UNITED,STATES
18935,31/12/2010,FLOWERS,FINAL,SERVICES,INC,5,UNITED,STATES
37700,31/12/2010,MAPLE,CORPORATION,1,CANADA
48614,31/12/2010,SERIAL,MGMT,L.P.,5,UNITED,STATES
1373,31/12/2010,AMORE,MGMT,GROUP,N,A,1,UNITED,STATES

如何避免在划定的字段宽度之外的空白处插入逗号?谢谢!

perl 在这里很方便:

perl -nE '                                     # read this bottom to top
    say join ",", 
        map {s/^\s+|\s+$//g; $_}               # trim leading/trailing whitespace
        /^(.{5}) (.{10}) (.{30}) (.{8}) (.*)/  # extract the fields
' simplefile.txt 
ratno,fdate,ratname,typecode,country
12346,31/12/2010,HARTZ,4,UNITED STATES
12444,31/12/2010,CHRISTIE,5,UNITED STATES
12527,31/12/2010,HILL AIR,4,UNITED STATES
15000,31/12/2010,TOKUGAVA  INC.,5,JAPAN
37700,31/12/2010,HARTLAND,1,UNITED KINGDOM
37700,31/12/2010,WILDER,1,UNITED STATES
18935,31/12/2010,FLOWERS FINAL SERVICES INC,5,UNITED STATES
37700,31/12/2010,MAPLE CORPORATION,1,CANADA
48614,31/12/2010,SERIAL MGMT  L.P.,5,UNITED STATES
1373,31/12/2010,AMORE MGMT GROUP N A,1,UNITED STATES

尽管如此,对于正确的 CSV,我们需要对包含逗号或引号的字段保持谨慎。如果我对文件的内容感到不太安全,我会使用这个 map 块:

map {s/^\s+|\s+$//g; s/"/""/g; qq("$_")}

输出

"ratno","fdate","ratname","typecode","country"
"12346","31/12/2010","HARTZ","4","UNITED STATES"
"12444","31/12/2010","CHRISTIE","5","UNITED STATES"
"12527","31/12/2010","HILL AIR","4","UNITED STATES"
"15000","31/12/2010","TOKUGAVA  INC.","5","JAPAN"
"37700","31/12/2010","HARTLAND","1","UNITED KINGDOM"
"37700","31/12/2010","WILDER","1","UNITED STATES"
"18935","31/12/2010","FLOWERS FINAL SERVICES INC","5","UNITED STATES"
"37700","31/12/2010","MAPLE CORPORATION","1","CANADA"
"48614","31/12/2010","SERIAL MGMT  L.P.","5","UNITED STATES"
"1373","31/12/2010","AMORE MGMT GROUP N A","1","UNITED STATES"

您的尝试很好,但 FIELDWIDTHS 内置变量需要 gawk (gnu awk)。呆呆地看着:

$ gawk -v FIELDWIDTHS="5 11 31 9 16" -v OFS=',' '{=;print}' file

ratno,      fdate, ratname                       , typecode, country
12346, 31/12/2010, HARTZ                         ,     4   , UNITED STATES
12444, 31/12/2010, CHRISTIE                      ,     5   , UNITED STATES
12527, 31/12/2010, HILL AIR                      ,     4   , UNITED STATES

假设您不想要多余的空格,您可以这样做:

$ gawk -v FIELDWIDTHS="5 11 31 9 16" -v OFS=',' '{for (i=1; i<=NF; ++i) gsub(/^ *| *$/, "", $i)}1' file
ratno,fdate,ratname,typecode,country
12346,31/12/2010,HARTZ,4,UNITED STATES
12444,31/12/2010,CHRISTIE,5,UNITED STATES
12527,31/12/2010,HILL AIR,4,UNITED STATES

如果您没有 gnu awk,您可以使用以下方法获得相同的结果:

$ awk -v fieldwidths="5 11 31 9 16" '
BEGIN { OFS=","; split(fieldwidths, widths) }
{
    rec = [=12=]
    [=12=] = ""
    start = 1;
    for (i=1; i<=length(widths); ++i) {
        $i = substr(rec, start, widths[i])
        gsub(/^ *| *$/, "", $i)
        start += widths[i]
    }
}1' file

ratno,fdate,ratname,typecode,country
12346,31/12/2010,HARTZ,4,UNITED STATES
12444,31/12/2010,CHRISTIE,5,UNITED STATES
12527,31/12/2010,HILL AIR,4,UNITED STATES