从字符串中删除控制、隐藏、不需要的字符

Question

请在我受到打击之前回答，因为还有其他类似我的 Whosebug 问题，但它们不起作用。我试图从入站邮件中删除不需要的字符，但没有成功。我不知道这些字符是什么或代表什么，但是，它们似乎像回车 returns 和换行符或换行符一样分解数据。我需要保留除末尾以外的所有空格。我看到的字符是 ^M 和 ^C。有时一起使用，有时单独使用。

我的测试代码基本上来自于观察其他类似的问题。

String msg = exchange.getIn().getBody(String.class);

log.info("Message before apply filter: " + msg);
filteredMessage = msg.replaceAll("[^\x00-\x7F]","");
log.info("Remove non-ASCII characters: " + filteredMessage);
filteredMessage = msg.replaceAll("[\p{C}]","");
log.info("Remove all Control characters: " + filteredMessage);
filteredMessage = msg.replaceAll("[\p{Cntrl}\p{Cc}\p{Cf}\p{Co}\p{Cn}]","");
log.info("Remove some Control characters: " + filteredMessage);
filteredMessage = msg.replaceAll("[^\p{Print}]","");
log.info("Remove non printable characters: " + filteredMessage);
filteredMessage = msg.trim();
log.info("Trim: " + filteredMessage);
filteredMessage = msg.replaceAll("\cM","");
log.info("Remove ^M Control characters: " + filteredMessage);
filteredMessage = msg.replaceAll("^M","");
log.info("Remove ^M Control characters: " + filteredMessage);

exchange.getIn().setBody(filteredMessage);

示例数据文件：

A   291511191831421742XXXXXXXXXXWRN/WN18111917420077000009ENG 2 IGN B FAULT^M ^C

A   056611191832641742XXXXXXXXXXFLR/FR18111917410032470002BRK TEMP SENSOR4(6GW)/  BTMU(2GW)^M/IDBSCU 1^M  ^C

A   080011191830061749XXXXXXXXXXMPF/AN.N306DN/FIDAL800    /DM181119142800/DAKSMF/DSKMSP/WN18111916310034000006NAV ATC/XPDR 1 FAULT^M,18111917480032000009BRAKES HOT^M/FR18111916310034523306ATC 1(1SH1)^M/IDATC 1^M/FR18111916310034723406ATC1(1SH1)/TCAS(1000SG)^M/IDTCAS^M/FR18111917120022833406AFS:FMGC2^M/IDAFS 1^M,IR 1^M,IR 2^M,IR 3^M/FR18111917120022833406AFS:FMGC1^M/IDAFS 1^M,IR 1^M,IR 2^M,IR 3^M ^C

我的过滤器不起作用。这是结果。就像正则表达式根本不起作用或者我在做一些愚蠢的事情。谢谢大家！

 Message before apply filter: A   056611191832641742XXXXXXXXXXFLR/FR18111917410032470002BRK TEMP SENSOR4(6GW)/  BTMU(2GW)^M/IDBSCU 1^M  ^C

Remove non-ASCII characters: A   056611191832641742XXXXXXXXXXFLR/FR18111917410032470002BRK TEMP SENSOR4(6GW)/  BTMU(2GW)^M/IDBSCU 1^M  ^C

Remove all Control characters: A   056611191832641742XXXXXXXXXXFLR/FR18111917410032470002BRK TEMP SENSOR4(6GW)/  BTMU(2GW)^M/IDBSCU 1^M  ^C

Remove some Control characters: A   056611191832641742XXXXXXXXXXFLR/FR18111917410032470002BRK TEMP SENSOR4(6GW)/  BTMU(2GW)^M/IDBSCU 1^M  ^C

Remove non printable characters: A   056611191832641742XXXXXXXXXXFLR/FR18111917410032470002BRK TEMP SENSOR4(6GW)/  BTMU(2GW)^M/IDBSCU 1^M  ^C

Trim: A   056611191832641742XXXXXXXXXXFLR/FR18111917410032470002BRK TEMP SENSOR4(6GW)/  BTMU(2GW)^M/IDBSCU 1^M  ^C

Remove ^M Control characters: A   056611191832641742XXXXXXXXXXFLR/FR18111917410032470002BRK TEMP SENSOR4(6GW)/  BTMU(2GW)^M/IDBSCU 1^M  ^C

Remove ^M Control characters: A   056611191832641742XXXXXXXXXXFLR/FR18111917410032470002BRK TEMP SENSOR4(6GW)/  BTMU(2GW)^M/IDBSCU 1^M  ^C

Answer 1

尝试以下方法，看看效果如何：

String msg = exchange.getIn().getBody(String.class);

log.info("Message before apply filter: " + msg);
filteredMessage = msg.replaceAll("[^\x00-\x7F]","");
log.info("Remove non-ASCII characters: " + filteredMessage);
filteredMessage =filteredMessage.replaceAll("[\p{C}]","");
log.info("Remove all Control characters: " + filteredMessage);
filteredMessage = filteredMessage.replaceAll("[\p{Cntrl}\p{Cc}\p{Cf}\p{Co}\p{Cn}]","");
log.info("Remove some Control characters: " + filteredMessage);
filteredMessage = filteredMessage.replaceAll("[^\p{Print}]","");
log.info("Remove non printable characters: " + filteredMessage);
filteredMessage = filteredMessage.trim();
log.info("Trim: " + filteredMessage);
filteredMessage = filteredMessage.replaceAll("\cM","");
log.info("Remove ^M Control characters: " + filteredMessage);
filteredMessage = filteredMessage.replaceAll("^M","");
log.info("Remove ^M Control characters: " + filteredMessage);

在此之后，如果您仍然看到不需要的字符，则需要使用转义字符 \ 来转义反斜杠和其他元字符：

<>()[]{}\^-=$!|?*+.

所以你需要，例如：.replaceALl("\^M","");

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