为图表收缩数据库中的响应数据
shrink response data from database for diagram
我正在尝试为图表缩小 nodejs 中的数据,但不知道什么是最好的方法。我想创建一个函数来获取原始数据并将总值缩小 X 天作为示例:
数据:
{ time: '2018-10-29', total: 8 }
{ time: '2018-10-30', total: 9 }
{ time: '2018-10-31', total: 10 }
{ time: '2018-11-1', total: 4 }
{ time: '2018-11-2', total: 21 }
{ time: '2018-11-3', total: 21 }
{ time: '2018-11-4', total: 4 }
{ time: '2018-11-5', total: 7 }
{ time: '2018-11-6', total: 14 }
{ time: '2018-11-7', total: 11 }
{ time: '2018-11-8', total: 15 }
{ time: '2018-11-9', total: 14 }
{ time: '2018-11-10', total: 23 }
{ time: '2018-11-11', total: 13 }
{ time: '2018-11-12', total: 6 }
{ time: '2018-11-13', total: 14 }
{ time: '2018-11-14', total: 17 }
{ time: '2018-11-15', total: 16 }
{ time: '2018-11-16', total: 16 }
{ time: '2018-11-17', total: 21 }
{ time: '2018-11-18', total: 6 }
{ time: '2018-11-19', total: 12 }
{ time: '2018-11-20', total: 11 }
{ time: '2018-11-21', total: 15 }
{ time: '2018-11-22', total: 15 }
{ time: '2018-11-23', total: 14 }
{ time: '2018-11-24', total: 25 }
{ time: '2018-11-25', total: 1 }
如果我想将此数据缩减为 10 天,则为 28/10 = Math.round(2.8),因此每个 3 将合并 return。但问题是我如何将其编码。
感谢任何建议
您可以尝试这样的操作:
const getDataInBucket = (bucketIndex, data) => data.filter((obj, i) => i >= bucketSize*bucketIndex && i<bucketSize*(bucketIndex+1));
然后你可以这样称呼它:
getDataInBucket(0, data); // first 10 elements
getDataInBucket(1, data); // second 10 elements
getDataInBucket(2, data); // rest 8 elements
我正在尝试为图表缩小 nodejs 中的数据,但不知道什么是最好的方法。我想创建一个函数来获取原始数据并将总值缩小 X 天作为示例:
数据:
{ time: '2018-10-29', total: 8 }
{ time: '2018-10-30', total: 9 }
{ time: '2018-10-31', total: 10 }
{ time: '2018-11-1', total: 4 }
{ time: '2018-11-2', total: 21 }
{ time: '2018-11-3', total: 21 }
{ time: '2018-11-4', total: 4 }
{ time: '2018-11-5', total: 7 }
{ time: '2018-11-6', total: 14 }
{ time: '2018-11-7', total: 11 }
{ time: '2018-11-8', total: 15 }
{ time: '2018-11-9', total: 14 }
{ time: '2018-11-10', total: 23 }
{ time: '2018-11-11', total: 13 }
{ time: '2018-11-12', total: 6 }
{ time: '2018-11-13', total: 14 }
{ time: '2018-11-14', total: 17 }
{ time: '2018-11-15', total: 16 }
{ time: '2018-11-16', total: 16 }
{ time: '2018-11-17', total: 21 }
{ time: '2018-11-18', total: 6 }
{ time: '2018-11-19', total: 12 }
{ time: '2018-11-20', total: 11 }
{ time: '2018-11-21', total: 15 }
{ time: '2018-11-22', total: 15 }
{ time: '2018-11-23', total: 14 }
{ time: '2018-11-24', total: 25 }
{ time: '2018-11-25', total: 1 }
如果我想将此数据缩减为 10 天,则为 28/10 = Math.round(2.8),因此每个 3 将合并 return。但问题是我如何将其编码。
感谢任何建议
您可以尝试这样的操作:
const getDataInBucket = (bucketIndex, data) => data.filter((obj, i) => i >= bucketSize*bucketIndex && i<bucketSize*(bucketIndex+1));
然后你可以这样称呼它:
getDataInBucket(0, data); // first 10 elements
getDataInBucket(1, data); // second 10 elements
getDataInBucket(2, data); // rest 8 elements