T-SQL - 运行 每个项目总数
T-SQL - Running total per project
我有这个简化的 table 结构：
我需要生成一个聚合结果，对每个 project/period 的交易求和 - 并且每个项目的总计 运行。我添加了列 TransactionCountInPeriod
如何编写查询以获得这样的结果：
这是我对查询的了解...我不知道如何根据 ProjectId.
执行 运行 总计
SELECT
prj.Id AS ProjectId,
p.Id AS PeriodId,
SUM(t.Amount) AS SumInPeriod--,
--SUM(t.Amount) OVER (PARTITION BY prj.Id) AS RunningTotal
--COUNT(t.*) AS TransactionCountInPeriod
FROM
Periods p
CROSS JOIN Projects prj
LEFT OUTER JOIN Transactions t ON p.Id = t.PeriodId
GROUP BY
prj.Id,
p.Id
ORDER BY
prj.Id,
p.Id
架构和测试数据
CREATE TABLE [dbo].[Periods](
[Id] [int] NOT NULL
)
GO
CREATE TABLE [dbo].[Projects](
[Id] [int] IDENTITY(1,1) NOT NULL,
[Name] [varchar](50) NOT NULL
)
GO
CREATE TABLE [dbo].[Transactions](
[Id] [int] IDENTITY(1,1) NOT NULL,
[ProjectId] [int] NOT NULL,
[PeriodId] [int] NOT NULL,
[Amount] [decimal](18, 0) NOT NULL
)
GO
INSERT [dbo].[Periods] ([Id]) VALUES (201801)
GO
INSERT [dbo].[Periods] ([Id]) VALUES (201802)
GO
INSERT [dbo].[Periods] ([Id]) VALUES (201803)
GO
INSERT [dbo].[Periods] ([Id]) VALUES (201804)
GO
INSERT [dbo].[Periods] ([Id]) VALUES (201805)
GO
SET IDENTITY_INSERT [dbo].[Projects] ON
GO
INSERT [dbo].[Projects] ([Id], [Name]) VALUES (1, N'Alpha')
GO
INSERT [dbo].[Projects] ([Id], [Name]) VALUES (2, N'Beta')
GO
SET IDENTITY_INSERT [dbo].[Projects] OFF
GO
SET IDENTITY_INSERT [dbo].[Transactions] ON
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (1, 1, 201801, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (2, 1, 201801, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (3, 1, 201802, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (4, 1, 201803, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (5, 1, 201803, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (6, 1, 201804, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (7, 2, 201801, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (8, 2, 201801, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (12, 2, 201804, CAST(100 AS Decimal(18, 0)))
GO
SET IDENTITY_INSERT [dbo].[Transactions] OFF
GO
（我会创建一个 sql fiddle，但是当我尝试时它总是崩溃...）
您可以使用 SUM window 函数计算 运行 总数。
DECLARE @Periods TABLE(
[Id] [int] NOT NULL
)
DECLARE @Projects TABLE(
[Id] [int] NOT NULL,
[Name] [varchar](50) NOT NULL
)
DECLARE @Transactions TABLE(
[Id] [int] NOT NULL,
[ProjectId] [int] NOT NULL,
[PeriodId] [int] NOT NULL,
[Amount] [decimal](18, 0) NOT NULL
)
INSERT @Periods ([Id]) VALUES (201801)
INSERT @Periods ([Id]) VALUES (201802)
INSERT @Periods ([Id]) VALUES (201803)
INSERT @Periods ([Id]) VALUES (201804)
INSERT @Periods ([Id]) VALUES (201805)
INSERT @Projects ([Id], [Name]) VALUES (1, N'Alpha')
INSERT @Projects ([Id], [Name]) VALUES (2, N'Beta')
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (1, 1, 201801, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (2, 1, 201801, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (3, 1, 201802, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (4, 1, 201803, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (5, 1, 201803, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (6, 1, 201804, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (7, 2, 201801, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (8, 2, 201801, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (12, 2, 201804, CAST(100 AS Decimal(18, 0)))
select
pr.Id as ProjectId
, pe.Id as PeriodId
, isnull(tr.SumAmount, 0) as SumInPeriod
, isnull(sum(tr.SumAmount) over(partition by pr.Id order by pe.Id), 0) as RunningTotal
, tr.TransactionsCount as TransactionCountInPeriod
from @Projects pr
cross join @Periods pe
outer apply (select sum(t.Amount) as SumAmount, count(*) as TransactionsCount from @Transactions t where t.ProjectId = pr.Id and t.PeriodId = pe.Id) tr
order by ProjectId, PeriodId
最简单的选择是使用 sum...over。
你在哪里非常接近 - 但你不需要分组依据，你需要将 order by 添加到 over 子句以获得 运行 总数 - 像这样：
SELECT pr.Id As ProjectId,
pe.Id As PeriodId,
SUM(Amount) OVER(PARTITION BY pe.Id, pr.Id) AS SumInPeriod,
SUM(Amount) OVER(PARTITION BY pr.Id ORDER BY pe.Id) AS RunningTotal,
COUNT(Amount) OVER(PARTITION BY pe.Id, pr.Id) TransactionCountInPeriod
FROM (
Periods pe
CROSS JOIN projects as pr
)
LEFT JOIN Transactions tr
ON pe.Id = tr.PeriodId
AND tr.ProjectId = pr.Id
ORDER BY pr.id, pe.id
我有这个简化的 table 结构：
我需要生成一个聚合结果，对每个 project/period 的交易求和 - 并且每个项目的总计 运行。我添加了列 TransactionCountInPeriod
如何编写查询以获得这样的结果：
这是我对查询的了解...我不知道如何根据 ProjectId.
执行 运行 总计SELECT
prj.Id AS ProjectId,
p.Id AS PeriodId,
SUM(t.Amount) AS SumInPeriod--,
--SUM(t.Amount) OVER (PARTITION BY prj.Id) AS RunningTotal
--COUNT(t.*) AS TransactionCountInPeriod
FROM
Periods p
CROSS JOIN Projects prj
LEFT OUTER JOIN Transactions t ON p.Id = t.PeriodId
GROUP BY
prj.Id,
p.Id
ORDER BY
prj.Id,
p.Id
架构和测试数据
CREATE TABLE [dbo].[Periods](
[Id] [int] NOT NULL
)
GO
CREATE TABLE [dbo].[Projects](
[Id] [int] IDENTITY(1,1) NOT NULL,
[Name] [varchar](50) NOT NULL
)
GO
CREATE TABLE [dbo].[Transactions](
[Id] [int] IDENTITY(1,1) NOT NULL,
[ProjectId] [int] NOT NULL,
[PeriodId] [int] NOT NULL,
[Amount] [decimal](18, 0) NOT NULL
)
GO
INSERT [dbo].[Periods] ([Id]) VALUES (201801)
GO
INSERT [dbo].[Periods] ([Id]) VALUES (201802)
GO
INSERT [dbo].[Periods] ([Id]) VALUES (201803)
GO
INSERT [dbo].[Periods] ([Id]) VALUES (201804)
GO
INSERT [dbo].[Periods] ([Id]) VALUES (201805)
GO
SET IDENTITY_INSERT [dbo].[Projects] ON
GO
INSERT [dbo].[Projects] ([Id], [Name]) VALUES (1, N'Alpha')
GO
INSERT [dbo].[Projects] ([Id], [Name]) VALUES (2, N'Beta')
GO
SET IDENTITY_INSERT [dbo].[Projects] OFF
GO
SET IDENTITY_INSERT [dbo].[Transactions] ON
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (1, 1, 201801, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (2, 1, 201801, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (3, 1, 201802, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (4, 1, 201803, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (5, 1, 201803, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (6, 1, 201804, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (7, 2, 201801, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (8, 2, 201801, CAST(100 AS Decimal(18, 0)))
GO
INSERT [dbo].[Transactions] ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (12, 2, 201804, CAST(100 AS Decimal(18, 0)))
GO
SET IDENTITY_INSERT [dbo].[Transactions] OFF
GO
（我会创建一个 sql fiddle，但是当我尝试时它总是崩溃...）
您可以使用 SUM window 函数计算 运行 总数。
DECLARE @Periods TABLE(
[Id] [int] NOT NULL
)
DECLARE @Projects TABLE(
[Id] [int] NOT NULL,
[Name] [varchar](50) NOT NULL
)
DECLARE @Transactions TABLE(
[Id] [int] NOT NULL,
[ProjectId] [int] NOT NULL,
[PeriodId] [int] NOT NULL,
[Amount] [decimal](18, 0) NOT NULL
)
INSERT @Periods ([Id]) VALUES (201801)
INSERT @Periods ([Id]) VALUES (201802)
INSERT @Periods ([Id]) VALUES (201803)
INSERT @Periods ([Id]) VALUES (201804)
INSERT @Periods ([Id]) VALUES (201805)
INSERT @Projects ([Id], [Name]) VALUES (1, N'Alpha')
INSERT @Projects ([Id], [Name]) VALUES (2, N'Beta')
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (1, 1, 201801, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (2, 1, 201801, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (3, 1, 201802, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (4, 1, 201803, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (5, 1, 201803, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (6, 1, 201804, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (7, 2, 201801, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (8, 2, 201801, CAST(100 AS Decimal(18, 0)))
INSERT @Transactions ([Id], [ProjectId], [PeriodId], [Amount]) VALUES (12, 2, 201804, CAST(100 AS Decimal(18, 0)))
select
pr.Id as ProjectId
, pe.Id as PeriodId
, isnull(tr.SumAmount, 0) as SumInPeriod
, isnull(sum(tr.SumAmount) over(partition by pr.Id order by pe.Id), 0) as RunningTotal
, tr.TransactionsCount as TransactionCountInPeriod
from @Projects pr
cross join @Periods pe
outer apply (select sum(t.Amount) as SumAmount, count(*) as TransactionsCount from @Transactions t where t.ProjectId = pr.Id and t.PeriodId = pe.Id) tr
order by ProjectId, PeriodId
最简单的选择是使用 sum...over。
你在哪里非常接近 - 但你不需要分组依据，你需要将 order by 添加到 over 子句以获得 运行 总数 - 像这样：
SELECT pr.Id As ProjectId,
pe.Id As PeriodId,
SUM(Amount) OVER(PARTITION BY pe.Id, pr.Id) AS SumInPeriod,
SUM(Amount) OVER(PARTITION BY pr.Id ORDER BY pe.Id) AS RunningTotal,
COUNT(Amount) OVER(PARTITION BY pe.Id, pr.Id) TransactionCountInPeriod
FROM (
Periods pe
CROSS JOIN projects as pr
)
LEFT JOIN Transactions tr
ON pe.Id = tr.PeriodId
AND tr.ProjectId = pr.Id
ORDER BY pr.id, pe.id