如何检查数组的元素是否存在于另一个数组数组中

Question

$result = array();
    $A= Array
   (
    [0] => Array
       (
        [id] => 1946
        [name] => cook
        [pic] => cookpic.png
       )

)
$B =  Array
 (
   [0] => Array
    (
        [id] => 1944
        [name] => driver
        [pic] => driver.png

    )

  [1] => Array
    (
        [id] => 934
        [name] => developer
        [pic] => developer.jpg
    )

[2] => Array
    (
        [id] => 1946
        [name] => cook
        [pic] => cookpic.png

    )

 )

我尝试过的：

   $result = !empty(array_intersect($a, $b));

我有两个数组，我用var_dump来显示它们并且可以在上面看到它们。

我想要实现的是，我想比较两个职业并且想要 $result 数组，这将是唯一的。现在，如果 Cook 不在 $B 中，那么 Cook 应该被推入 $B 数组，这将变为 $result 否则它不应该被推入。

Answer 1

做$result = !empty(array_intersect($a, $b));只会告诉你$a和$b

之间是否有共同元素

$result = array();
$a = array(
    array(
        "id" => 1946,
        "name" => "Cook", // upper case C
        "pic" => "cookpic.png"
    ),

    array(
        "id" => 1946,
        "name" => "cook", // lower case c
        "pic" => "cookpic.png"
    )
);

$b = array(
    array(
        "id" => 1944,
        "name" => "driver",
        "pic" => "driver.png"
    ),
    array(
        "id" => 934,
        "name" => "developer",
        "pic" => "developer.png"
    ),
    array(
        "id" => 1946,
        "name" => "cook", // lower case c
        "pic" => "cookpic.png"
    )
);

foreach ($a as $k => $v) {
    if (in_array($v, $b) == false) {
        array_push($result, $v);
    }
}

print_r($result);

您可以使用 array_diff，但它不适用于多维数组。所以你必须从头开始

编辑：

$result = array();
$a = array(
    array(
        "id" => 1946,
        "name" => "Cook", // upper case C
        "pic" => "cookpic.png"
    ),

    array(
        "id" => 1946,
        "name" => "cook", // lower case c
        "pic" => "cookpic.png"
    )
);

$b = array(
    array(
        "id" => 1944,
        "name" => "driver",
        "pic" => "driver.png"
    ),
    array(
        "id" => 934,
        "name" => "developer",
        "pic" => "developer.png"
    ),
    array(
        "id" => 1946,
        "name" => "cook", // lower case c
        "pic" => "cookpic.png"
    )
);

$m = array_merge($a, $b);
$result = array_map("unserialize", array_unique(array_map("serialize", $m)));
print_r($result);

合并两个数组，然后应用 array_unique 使用 array_map 删除重复项

Answer 2

对 comparison.And 使用 strcasecmp() 内置函数，然后使用 array_push()。您可以使用蛮力方法。但我相信你可以从中得到更好的答案。

$result=array();
$A[0]=array("id" => 1946, "name" => Cook, "pic" => cookpic.png);
$B[0]=array("id" => 1944, "name" => driver, "pic" => driver.png);
$B[1]=array("id" => 934, "name" => developer, "pic" => developer.jpg);
$B[2]=array("id" => 1946, "name" => cook, "pic" => cookpic.png);


foreach ($A as $key => $value) 
{
    foreach ($B as $key1 => $value1) 
    {
        if (!strcasecmp($value["name"], $value1["name"])) 
        {   array_push($result, $value);    }
    }
}

echo("<pre>");print_r($result);

如何检查数组的元素是否存在于另一个数组数组中

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