用于复杂负载的 Eclipse Xquery

Question

我有如下输入请求

 <Input>
    <BusinessObjects>
          <BusinessObject>
            <BusinessIdentifiers>
              <BusinessIdentifier>
                <BKey>BuCode</BKey>
                <BValue>CDC</BValue>
              </BusinessIdentifier>
              <BusinessIdentifier>
                <BKey>BuType</BKey>
                <BValue>123</BValue>
              </BusinessIdentifier>
              <BusinessIdentifier>
                <BKey>CsmNo</BKey>
                <BValue>857895</BValue>
              </BusinessIdentifier>
            </BusinessIdentifiers>
           </BusinessObject>
          <BusinessObject>
            <BusinessIdentifiers>
              <BusinessIdentifier>
                <BKey>BuCode</BKey>
                <BValue>CDC</BValue>
              </BusinessIdentifier>
              <BusinessIdentifier>
                <BKey>BuType</BKey>
                <BValue>123</BValue>
              </BusinessIdentifier>
              <BusinessIdentifier>
                <BKey>CsmNo</BKey>
                <BValue>34567</BValue>
              </BusinessIdentifier>
            </BusinessIdentifiers>
            </BusinessObject>      
        </BusinessObjects>
        </Input>

我需要形成如下模式的输出

<Output>
<BusinessObject>
<BIKey></BIKey>
<BKey></BIKey>
<Bvalue></Bvalue>
<BOID></BOID>
</BusinessObject>
</Output>

对于上面的payload 输出应该是

  <Output>
    <BusinessObjects>
    <BusinessObject>
    <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
    <BKey>BUCode</BKey>
    <Bvalue>CDC</Bvalue>
    <BOID>CDC:123:857895</BOID>
    </BusinessObject>
    <BusinessObject>
    <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
    <BKey>BUtype</BKey>
    <Bvalue>123</Bvalue>
    <BOID>CDC:123:857895</BOID>
    </BusinessObject>
    <BusinessObject>
    <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
    <BKey>CSMNo</BKey>
    <Bvalue>857895</Bvalue>
    <BOID>CDC:123:857895</BOID>
    </BusinessObject>
    <BusinessObject>
    <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
    <BKey>BUCode</BKey>
    <Bvalue>CDC</Bvalue>
    <BOID>CDC:123:34567</BOID>
    </BusinessObject>
    <BusinessObject>
    <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
    <BKey>BUtype</BKey>
    <Bvalue>123</Bvalue>
    <BOID>CDC:123:34567</BOID>
    </BusinessObject>
    <BusinessObject>
    <BIKey>CDC:123:857895|CDC:123:34567</BIKey>
    <BKey>CSMNo</BKey>
    <Bvalue>857895</Bvalue>
    <BOID>CDC:123:34567</BOID>
    </BusinessObject>
    </BusinessObjects>
    </Output>

我已经尝试在 Xquery 下获得相同的结果，但最终出现错误或不符合要求

<Ouput>
<BusinessObjects>
{
for $bi in Input/BusinessObjects/BusinessObject/BusinessIdentifiers/BusinessIdentifier
return
<BIKey>
    {
        string-join(
            for $bo in Input/BusinessObjects/BusinessObject return string-join($bo/BusinessIdentifiers/BusinessIdentifier/BValue, '|'),
            ':'
        )
    }
    </BIKey>
    <BKey>data {$bi/Bkey}</BKey>
    <Bvalue>data {$bi/Bvalue}</Bvalue>
    for $bo in Input/BusinessObjects/BusinessObject return <BOID>{string-join($bo//BValue, ':')}<BOID>

}
</BusinessObjects>
</Ouput>

输出字段说明如下 BIKey-->它由 'Business Identifier' 的所有 B 值与“:”连接而成，然后对于每个业务对象，它用“|”分隔 Bkey-->直接用bkey映射 Bvalue-->直接用B值映射 BOID--> 它必须为每个业务对象形成，需要将业务标识符的值 B 值与“:”连接起来任何建议，我相信我必须在这里有两个复杂的循环，但无法破解它。

感谢@Martin，他帮助我使用“ancestor”轴破解了这个问题，但有些 eclispe 无法识别“ancestor”。

谢谢

Answer 1

所有输出的 BIKey 都是相同的，因此我们可以在任何循环之外计算它并完成它。为此，我们将 BusinessObject 的所有 BValues 与 : 连接起来，并将每个 BusinessObject 的结果与 | 连接起来：

let $BIKey := string-join(for $bo in /Input/BusinessObjects/BusinessObject return string-join($bo/BusinessIdentifiers/BusinessIdentifier/BValue, ':'), '|')

BOID 将取决于我们正在处理的 BusinessObject，因此我们需要遍历这些对象，然后我们可以在此时提取 BOID：

let $BIKEY := [...]
for $bo in /Input/BusinessObjects/BusinessObject
  let $BOID := string-join($bo/BusinessIdentifiers/BusinessIdentifier/BValue, ':')

其余输出字段取决于 BusinessIdentifier，因此让我们也循环处理这些字段，return 每个 BusinessIdentifier 一个 BusinessObject :

let $BIKEY := [...]
for $bo in [...]
  let $BOID :=  [...]
  return for $bi in $bo/BusinessIdentifiers/BusinessIdentifier/
    return <BusinessObject>
             <BIKey>{$BIKEY}</BIKey>
             <BKey>{$bi/BKey}</BKey>
             <Bvalue>{$bi/Value}</Bvalue>
             <BOID>{$BOID}</BOID>
           </BusinessObject>

现在我们需要做的就是将这些输出的 BusinessObjects 包装到它们的父标签中：

<output><BusinessObjects>{
let $BIKEY := string-join(for $bo in /Input/BusinessObjects/BusinessObject return string-join($bo/BusinessIdentifiers/BusinessIdentifier/BValue, ':'), '|')
for $bo in /Input/BusinessObjects/BusinessObject
  let $BOID := string-join($bo/BusinessIdentifiers/BusinessIdentifier/BValue, ':')
  return
    for $bi in $bo/BusinessIdentifiers/BusinessIdentifier
    return <BusinessObject>
<BIKey>{$BIKEY}</BIKey>
<BKey>{$bi/BKey/text()}</BKey>
<Bvalue>{$bi/BValue/text()}</Bvalue>
<BOID>{$BOID}</BOID>
</BusinessObject>
}</BusinessObjects></output>

你可以test it here.

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