Q: yii2 dataProvider 不显示连接属性

Q: yii2 dataProvider doesn't display join attributes

我在 User 和 Thesis 之间有关系,我的 dataProvider 只在 Gridview 中显示用户属性而不是 thesis'ones。有没有比 ['attribute'] => ['table.attribute']?

更好的打印连接属性的方法

型号:

public function search($params)
{
    $query = Request::find()->joinWith('user')->joinWith('thesis')->where(['thesis.staff'=> Yii::$app->user->identity->id]);

    $dataProvider = new ActiveDataProvider([
        'query' => $query,
    ]);

    $this->load($params);

    if (!$this->validate()) {
        // uncomment the following line if you do not want to return any records when validation fails
        // $query->where('0=1');
        return $dataProvider;
    }

查看:

<?= GridView::widget([
    'dataProvider' => $dataProvider,
    'filterModel' => $searchModel,
    'columns' => [
        ['class' => 'yii\grid\SerialColumn'],

        //'id',
        'title',
        ['attribute' => 'thesis',
        'value' => 'thesis.title'],
        //'company',
        'description:ntext',
        'duration',
        ['attribute' => 'user'
        'value' => 'user.id'],
        //'requirements',
        //'course',
        'n_person',
        'ref_person',
        'is_visible:boolean',
        //'created_at',
        //'staff',

        ['class' => 'yii\grid\ActionColumn'],
    ],
]); ?>

控制器:

public function actionIndex()
{
    $searchModel = new SearchRequest();
    $dataProvider = $searchModel->search(Yii::$app->request->queryParams);

    return $this->render('index', [
        'searchModel' => $searchModel,
        'dataProvider' => $dataProvider,
    ]);
}

最好在 $this->load($params);

之后添加代码

我的例子是:

.
.
.
$this->load($params);
if (!$this->validate()) {
    // uncomment the following line if you do not want to return any records when validation fails
    // $query->where('0=1');
    return $dataProvider;
}
$query->joinWith('user');
$query->joinWith('thesis');
$query->andFilterWhere(['thesis.staff'=> Yii::$app->user->identity->id]);
.
.
.

您需要在模型中添加关系吸气剂。

在您的 Thesis 模型上,您需要添加类似

的内容
public function getUser0 () {
    return $this->hasOne(\your\user\model\location\User::className(), ['id' => 'user']);
}

当您调用 Thesis::user0 时,在您的模型上使用它会通过延迟加载用户关系来填充,在您的情况下,是这样的:

<?= GridView::widget([
    'dataProvider' => $dataProvider,
    'filterModel' => $searchModel,
    'columns' => [
        ['class' => 'yii\grid\SerialColumn'],
        /// ---- other attributes
        ['attribute' => 'user0.name'],
        /// ---- other attributes
    ],
]); ?>