Java：JOptionPane.showMessageDialog 有问题

Question

我正在制作一个简单的程序，它接受 3 个整数（n1、n2、n3）的输入，例如，如果这 3 个数字是 6、12、4，它应该 return：

Integers entered: 6,12,4  
Sum = 22  
Average = 7.33...  
Smallest = 4  
Largest = 12

这是使用 JOptionPane.showMessageDialog 在文本框中显示的。代码放在一个循环中，这样每输入 3 个整数，它就会 return 如上所示。但是，当我运行程序时，它显示以下内容：

Integers entered: 6,6,6  
Sum = 22  
Average = 7.33...  
Smallest = 6  
Largest = 6

n2、n3 的值，最小值和最大值表示 n1 的值。这是循环中给我带来问题的代码：

JOptionPane.showMessageDialog(null, title);
String num1 = JOptionPane.showInputDialog("Enter 1st integer: ");
int n1 = Integer.parseInt(num1);
String num2 = JOptionPane.showInputDialog("Enter 2nd integer: ");
int n2 = Integer.parseInt(num2);
String num3 = JOptionPane.showInputDialog("Enter 3rd integer: ");
int n3 = Integer.parseInt(num3);

int sum = n1 + n2 + n3; //find sum
double avg = (double)sum/3; //find average

//find smallest integer
int smallest = n1;
if(n2 < smallest) n2 = smallest;
if(n3 < smallest) n3 = smallest;

//find largest integer
int largest = n1;
if(n2 > largest) n2 = largest;
if(n3 > largest) n3 = largest;

JOptionPane.showMessageDialog(null, "Integers entered: " + n1 + ", " + n2 + ", " + n3 
                + "\nSum = " + sum
                + "\nAverage = " + avg
                + "\nSmallest = " + smallest
                + "\nLargest = " + largest);

如何修复它以便 n2、n3、smallest、largest 显示它们的正确值？

Answer 1

您将 smallest 和 largest 的值重新分配给 n2 或 n3，具体取决于计算结果...

if(n2 < smallest) n2 = smallest;
if(n3 < smallest) n3 = smallest;

//find largest integer
int largest = n1;
if(n2 > largest) n2 = largest;
if(n3 > largest) n3 = largest;

尝试更像...

if(n2 < smallest) smallest = n2;
if(n3 < smallest) smallest = n3;

//find largest integer
int largest = n1;
if(n2 > largest) largest = n2;
if(n3 > largest) largest = n3;

Java：JOptionPane.showMessageDialog 有问题

Java: problem with JOptionPane.showMessageDialog

java

int

joptionpane