类型 JSONArray 无法转换为 JSONObject

Question

当我调用我的服务网站时，我遇到了这个异常：类型 org.json.JSONArray 的 org.json.JSONException:Value[{}] 无法转换为 JSONObject

private void jsonParse(){
        String url="http://192.168.56.1:8095/rest/workouts/all";
        JsonObjectRequest request = new JsonObjectRequest(Request.Method.GET, url, null,
                new Response.Listener<JSONObject>() {
                    @Override
                    public void onResponse(JSONObject response) {
                        try {
                            JSONArray jsonArray = response.getJSONArray("");

                            for(int i = 0; i < jsonArray.length(); i++) {
                                JSONObject w = jsonArray.getJSONObject(i);

                                String title = w.getString("title");
                                String goal = w.getString("goal");

                                txtv.append(title + ", " + goal +"\n\n");
                            }
                        ...

顺便说一句，这是 JSON 格式

[{"id":"1","title":"title","goal":"goal","exercice":"Exercice 
1","difficulty":"Beginner","duration":"3","image":"..","description":"..."},]

Answer 1

您的 json 响应实际上是一个 JsonArray，因此您需要将代码更改为：

private void jsonParse(){
    String url="http://192.168.56.1:8095/rest/workouts/all";
    JsonArrayRequest request = new JsonArrayRequest(Request.Method.GET, url, null,
            new Response.Listener<JSONArray >() {
                @Override
                public void onResponse(JSONArray response) {
                    try {


                        for(int i = 0; i < response.length(); i++) {
                            JSONObject w = response.getJSONObject(i);

                            String title = w.getString("title");
                            String goal = w.getString("goal");

                            txtv.append(title + ", " + goal +"\n\n");
                        }

Answer 2

尝试

 JsonArrayRequest jsonArrayRequest = new JsonArrayRequest(
                    Request.Method.GET,
                    url,
                    null,
                    new Response.Listener<JSONArray>() {
                        @Override
                        public void onResponse(JSONArray response) {

                            for(int i = 0; i < response.length(); i++) {
                            JSONObject w = response.getJSONObject(i);

                            String title = w.getString("title");
                            String goal = w.getString("goal");

                            txtv.append(title + ", " + goal +"\n\n");
                             }

                            }catch (JSONException e){
                                e.printStackTrace();
                            }
                        }
                    },
                    new Response.ErrorListener(){
                        @Override
                        public void onErrorResponse(VolleyError error){
                            // Do something when error occurred

                        }
                    }
            );

Answer 3

虽然答案可以处理你的情况，但看看你的 JSON，它显然是一个数组而不是对象，你的 JSON 的正确格式可能是这样的：

{"id":"1","title":"title","goal":"goal","exercice":"Exercice1","difficulty":"Beginner","duration":"3","image":"..","description":"..."}

其中没有“[”、“]”和“,”。所以这是我的解决方案，如果它一直只接收一个对象，你应该改变你的API，只发送一个对象，就像我上面提到的那样，否则，最后的“，”是不正确的一个只有一个项目的数组，无论如何，您必须将模型更改为 except 数组 [您可以将其声明为列表，如：List<Model> myModelList] 以便解析器正常工作。

Answer 4

试试这个

try{

        JSONArray jsonArray = new JSONArray(response.string());
        for (int i=0;i<jsonArray.length();i++){

            String Title=jsonArray.getJSONObject(i).getString("title");
            String Goal=jsonArray.getJSONObject(i).getString("goal");

        }
    }
    catch (Exception e){
        e.printStackTrace();
    }

Answer 5

试试这个……应该是

JSONArray jsonarray = new JSONArray(response);

然后是

for(int i=0; i < jsonarray.length(); i++) {
   JSONObject jsonobject = jsonarray.getJSONObject(i);

   //your code
}

Answer 6

这是我找到的解决方案，谢谢大家♥..

    private void jsonParse(){
        String url="http://192.168.56.1:8095/rest/workouts/all";
        JsonArrayRequest jsonArrayRequest = new JsonArrayRequest(Request.Method.GET,url,null,
                new Response.Listener<JSONArray>() {
                    @Override
                    public void onResponse(JSONArray jsonArray) {
                        try {
                            
                            for(int i = 0; i < jsonArray.length(); i++) {


                                JSONObject jsonobject = jsonArray.getJSONObject(i);

                                String title = jsonobject.getString("title");
                                String goal = jsonobject.getString("goal");

                                txtv.append(title + ", " + goal +"\n\n");
                            }
                        } catch (JSONException e) {
                            e.printStackTrace();
                        }
                    }
                },
                new Response.ErrorListener() {
                    @Override
                    public void onErrorResponse(VolleyError error) {

                    }
                });
        mQueue.add(jsonArrayRequest);
    }

类型 JSONArray 无法转换为 JSONObject

Type JSONArray cannot be converted to JSONObject

android

json

android-studio

android-volley

android-json