根据 Laravel 中数组的值和总和区分数组
Differentiate Array base on Value And Sum Of Array in Laravel
我有数组,首先我想根据站点(键)进行区分,站点不限于 1 或 2
然后是站点的期初余额和期末余额之和
像所有网站(888) total_balance = opening_balance + closing_balance
(999) total_balance = opening_balance + closing_balance
"games": [
{
"id": 240,
"user_id": 1,
"site": "888",
"opening_balance": 5,
"closing_balance": 6
},
{
"id": 243,
"user_id": 1,
"site": "999",
"opening_balance": 3,
"closing_balance": 4
},
{
"id": 244,
"user_id": 1,
"site": "888",
"opening_balance": 5,
"closing_balance": 6
},
并且想要像这样的输出
(站点 => 888,total_balance => 22,站点 => 999,total_balance => 7
(它可以是 b 字符串))
我试过的代码:
{
$collection = collect(Site::all())->map(function($item , $key){
return $item["name"];
});
$record = Game::whereIn('site',$collection)->get();
dd($record);
/*$bySite = array();
foreach ($record as $key => $item) {
if(!isset($bySite[$item['site']])) {
$bySite[$item['site']] = array();
}
$bySite[$item['site']][$key] = $item;
}*/
}
在我评论输出的这段代码之后
但我不知道这个
的总和
{
"888": {
"0": {
"id": 240,
"user_id": 1,
"site": "888",
"opening_balance": 5,
"closing_balance": 6
},
"2": {
"id": 244,
"user_id": 1,
"site": "888",
"opening_balance": 5,
"closing_balance": 6
},
},
"999": {
"1": {
"id": 243,
"user_id": 1,
"site": "999",
"opening_balance": 3,
"closing_balance": 4,
您可以使用 Laravel 集合实现此目的。
$games = [
[
"id" => 240,
"user_id" => 1,
"site" => "888",
"opening_balance" => 5,
"closing_balance" => 6
],
[
"id" => 243,
"user_id" => 1,
"site" => "999",
"opening_balance" => 3,
"closing_balance" => 4
],
[
"id" => 244,
"user_id" => 1,
"site" => "888",
"opening_balance" => 5,
"closing_balance" => 6
]
];
$games = collect($games);
$games = $games->groupBy('site')->map(function($game, $key){
return [
'site' => $key,
'total_balance' => $game->sum('opening_balance') + $game->sum('closing_balance'),
];
})->values();
dd($games->toArray());
输出将是,
array:2 [▼
0 => array:2 [▼
"site" => 888
"total_balance" => 22
]
1 => array:2 [▼
"site" => 999
"total_balance" => 7
]
]
步
1.foreach($集合)
2. 将值求和并存储在数组中,如 $collection->sum('opening_balance'), ($collection->sum('closing_balance')
3.然后对变量求和
4.停止循环
5. 然后 $final = $final['site'] 。 “=>”。 $最终['sum'];
我有数组,首先我想根据站点(键)进行区分,站点不限于 1 或 2 然后是站点的期初余额和期末余额之和 像所有网站(888) total_balance = opening_balance + closing_balance (999) total_balance = opening_balance + closing_balance
"games": [
{
"id": 240,
"user_id": 1,
"site": "888",
"opening_balance": 5,
"closing_balance": 6
},
{
"id": 243,
"user_id": 1,
"site": "999",
"opening_balance": 3,
"closing_balance": 4
},
{
"id": 244,
"user_id": 1,
"site": "888",
"opening_balance": 5,
"closing_balance": 6
},
并且想要像这样的输出 (站点 => 888,total_balance => 22,站点 => 999,total_balance => 7 (它可以是 b 字符串))
我试过的代码:
{
$collection = collect(Site::all())->map(function($item , $key){
return $item["name"];
});
$record = Game::whereIn('site',$collection)->get();
dd($record);
/*$bySite = array();
foreach ($record as $key => $item) {
if(!isset($bySite[$item['site']])) {
$bySite[$item['site']] = array();
}
$bySite[$item['site']][$key] = $item;
}*/
}
在我评论输出的这段代码之后 但我不知道这个
的总和{
"888": {
"0": {
"id": 240,
"user_id": 1,
"site": "888",
"opening_balance": 5,
"closing_balance": 6
},
"2": {
"id": 244,
"user_id": 1,
"site": "888",
"opening_balance": 5,
"closing_balance": 6
},
},
"999": {
"1": {
"id": 243,
"user_id": 1,
"site": "999",
"opening_balance": 3,
"closing_balance": 4,
您可以使用 Laravel 集合实现此目的。
$games = [
[
"id" => 240,
"user_id" => 1,
"site" => "888",
"opening_balance" => 5,
"closing_balance" => 6
],
[
"id" => 243,
"user_id" => 1,
"site" => "999",
"opening_balance" => 3,
"closing_balance" => 4
],
[
"id" => 244,
"user_id" => 1,
"site" => "888",
"opening_balance" => 5,
"closing_balance" => 6
]
];
$games = collect($games);
$games = $games->groupBy('site')->map(function($game, $key){
return [
'site' => $key,
'total_balance' => $game->sum('opening_balance') + $game->sum('closing_balance'),
];
})->values();
dd($games->toArray());
输出将是,
array:2 [▼
0 => array:2 [▼
"site" => 888
"total_balance" => 22
]
1 => array:2 [▼
"site" => 999
"total_balance" => 7
]
]
步 1.foreach($集合) 2. 将值求和并存储在数组中,如 $collection->sum('opening_balance'), ($collection->sum('closing_balance') 3.然后对变量求和 4.停止循环 5. 然后 $final = $final['site'] 。 “=>”。 $最终['sum'];