JSON 获取完整数字

Question

我有一个 BigInteger 变量，例如chipertext:

println "chipherTotalAmount= "+chipertext

结果：

然后我解析为JSON，结果是

如何获得完整数字的值？

这是我的网络应用代码。

def registerItem = RegisterItem.where {
    (dateReceivedItem >= fromDate && dateReceivedItem < toDate)
}.list()

println "registerItem.size = "+registerItem.size()

for (int x = 0; x < registerItem.size(); x++){

    RSA rsa =  new RSA()
    println "x noata .clas = "+registerItem[x].noNota.class
    // BigInteger plaintext = new BigInteger( registerItem[x].noNota.getBytes())

    publickey = new BigInteger(cifuser.publicKey)
    newn = new BigInteger(cifuser.newn)
    privatekey = new BigInteger(cifuser.privateKey)

    BigInteger NoNota = new BigInteger(registerItem[x].noNota.getBytes());
    BigInteger chipherNoNota = rsa.encrypt(NoNota, publickey, newn);
    println "chipherNoNota = "+chipherNoNota

    def totalmountString = registerItem[x].totalAmount.toString()
    println "totalmountString = "+totalmountString
    println "totalmountString = "+totalmountString.class
    BigInteger TotalAmount = new BigInteger(totalmountString.getBytes());
    BigInteger chipherTotalAmount = rsa.encrypt(TotalAmount, publickey, newn);
    println "chipherTotalAmount = "+chipherTotalAmount

    BigInteger SenderName = new BigInteger(registerItem[x].senderName.getBytes());
    BigInteger chipherSenderName = rsa.encrypt(SenderName, publickey, newn);
    println "chipherSenderName = "+chipherSenderName

    registerItem[x].noNota = chipherNoNota.toString()
    registerItem[x].totalAmount = chipherTotalAmount //i cannot parse this to String because at my domain totalAmount was BigInteger
    registerItem[x].senderName = chipherSenderName.toString()
    registerItem[x].discard()
}

这是我的域名

class RegisterItem implements Serializable{

    String noNota
    City destination
    Date dateReceivedItem

    String senderName
    String noTelpSender
    String noHpSender
    String emailSender
    String addressSender
    String descriptionSender

    String receiverName
    String noTlpReceiver
    String noHpReceiver
    String emailReceiver
    String addressReceiver
    String descriptionReceiver

    String deleteFlag = "N"

    BigInteger totalAmount

    String isPay = "Y"

    String useDefault = "Y"

    Date dateCreated
    Date lastUpdated

    String updatedBy = ""
    String createdBy

    static constraints = {
        noTelpSender(nullable:true,blank:true)
        noHpSender(nullable:true,blank:true)
        emailSender(nullable:true,blank:true)
        addressSender(nullable:true,blank:true)
        descriptionSender(nullable:true,blank:true)

        noTlpReceiver(nullable:true,blank:true)
        noHpReceiver(nullable:true,blank:true)
        emailReceiver(nullable:true,blank:true)
        addressReceiver(nullable:true,blank:true)
        descriptionReceiver(nullable:true,blank:true)

        createdBy(blank: false, maxSize: 50)
        lastUpdated(nullable: true)
    }

    def beforeInsert = {
        // createdBy = springSecurityService.principal.username
        dateCreated = new Date()
    }
    def beforeUpdate = {
        // updatedBy = springSecurityService.principal.username
        lastUpdated = new Date()
    }
}

Answer 1

如果我是你并且热衷于无损转换，我会将其解析为 String 并使用以下方式将其作为 String 发送：

String.valueOf(bigInt);

或

bigInt.toString();

JSON 获取完整数字

JSON get full digit number

grails

json