Linux 倒计时关机。（同时制作）

Question

你好，我想创建一个脚本，在特定时间（例如 15 秒）后关闭 Linux，并在终端中显示倒计时（Linux 在 15 秒后关闭。）。它必须与 while 一起。

Answer 1

您可以使用以下内容：

#!/bin/bash
COUNTER=15
while [ 1 ] 
do
    if [ ${COUNTER} -eq 0 ]
    then
        break
    fi
    echo "Linux is shutting down after ${COUNTER}s."
    sleep 1
    COUNTER=$( echo "${COUNTER}-1" | bc )
done
sudo poweroff

Answer 2

如果您真的想在屏幕上显示计数器，可以这样做：

#!/bin/bash

seconds=15
echo "Linux is shutting down after ${seconds}s"          
date_1=$((`date +%s` + $seconds))

while [ "$date_1" -ge `date +%s` ]; do
echo -ne "$(date -u --date @$(($date_1 - `date +%s` )) +%H:%M:%S)\r"
     done

echo -e "Do you really want to shutdown the system? Press [Y/y] to shutdown or [n/N] to cancel/exit:" 
read var
if [[ "$var" == "y" ]] || [[ "$var" == "Y" ]]
then
sudo poweroff
elif [[ "$var" == "n" ]] || [[ "$var" == "N" ]]
then
exit 1
fi

基本上，它会接受用户 [Y/y] 关闭和 [n/N] 退出。

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