读取文件后cout不打印

Question

出于某种原因，我的 cout 无法正常工作。我认为这与需要刷新的缓冲区有关。我试图在阅读文件后添加一个 cout << flush 但这并没有解决它。我唯一打印的地方是 for 循环中的 main() 。这是我从这些印刷品中得到的输出。

Aeberg
Aaren
Aaron
Full Name
 Aaron

阿龙前后各有一个space。所以只打印姓氏。

#include <iostream>
#include <fstream>
#include <queue>
#include <time.h>

using namespace std;

const int SIZE = 50000;

void initFirst(string first[]);
void initMiddle(string middle[]);
void initLast(string last[]);

int main()
{
  srand(time(NULL));
  ifstream in;
  ofstream out;

  string first[SIZE];
  string middle[SIZE];
  string last[SIZE];

  initFirst(first);
  initMiddle(middle);
  initLast(last);
  string x;

  for(int i = 0; i < 1; i++)
  {
    cout << first[i] << endl;
    cout << middle[i] << endl;
    cout << last[i] << endl;

    cout << "Full Name" << endl;
    cout << first[i] << " " << middle[i] << " " << last[i] << endl; // Isn't printing correctly here
  }

  return 1;
}

  void
initFirst(string first[])
{
  ifstream file("names.txt");
  string line;
  int counter = 0;

  if(file.is_open())
  {
    while(getline(file, line))
    {
      first[counter] = line;
      counter++;
    }
    file.close();
  }
  int left = SIZE - counter;
  int random[left];

  for(int i = 0; i < left; i++)
    random[i] = rand() % counter;

  for(int i = counter; i < SIZE; i++)
    first[i] = first[random[i-counter]];
}

void
initMiddle(string middle[])
{
  ifstream file("first-names.txt");
  string line;
  int counter = 0;

  if(file.is_open())
  {
    while(getline(file, line))
    {
      middle[counter] = line;
      counter++;
    }
    file.close();
  }

  int left = SIZE - counter;
  int random[left];

  for(int i = 0; i < left; i++)
    random[i] = rand() % counter;

  for(int i = counter; i < SIZE; i++)
    middle[i] = middle[random[i-counter]];
}

void
initLast(string last[])
{
  ifstream file("middle-names.txt");
  string line;
  int counter = 0;

  if(file.is_open())
  {
    while(getline(file, line))
    {
      last[counter] = line;
      counter++;
    }
    file.close();
  }

  int left = SIZE - counter;
  int random[left];

  for(int i = 0; i < left; i++)
    random[i] = rand() % counter;

  for(int i = counter; i < SIZE; i++)
    last[i] = last[random[i-counter]];
}

Answer 1

我建议稍微改进一下你的程序。

不需要三个函数init，一个就够了。只需传递文件名参数即可。
不要使用大的静态数组，例如 string first[SIZE] - 这会导致堆栈溢出。请改用向量。
一些错误已修复，未编译行，例如 int random[left];
你根本不需要 random 数组

#include <cstdint>
#include <vector>
#include <string>
#include <fstream>
#include <iostream>
#include <time.h>

const size_t SIZE = 50000;
using strings = std::vector<std::string>; // 'array' of strings with dynamic size

void initFromFile(const std::string &fname, strings &arr)
{
    std::ifstream file(fname);
    std::string line;

    while(getline(file, line))
        arr.push_back(line);

    size_t n = arr.size();
    if(n == 0)
        return;
    for(auto i = 0; i < SIZE-n; i++)
        arr.push_back(arr[rand() % n]);
}


int main()
{
    using std::cout;
    using std::endl;
    srand(time(NULL));
    strings first, middle, last;

    initFromFile("names.txt", first);
    initFromFile("first-names.txt", middle);
    initFromFile("middle-names.txt", last);    

    for(auto i = 0U; i < first.size(); i++)
    {
        cout << first[i] << endl << middle[i] << endl << last[i] << endl;
        cout << "Full Name" << endl;
        cout << first[i] << " " << middle[i] << " " << last[i] << endl; 
    }
}

读取文件后cout不打印

cout not printing after reading files

c++

cout