如何结合 if else 和 try except in python
How to combine if else with try except in python
我的 class MyMatch 中有函数列表,在函数
中组合 try except 和 if else 时出现缩进错误
这是我的比赛Class
class MyMatch(object):
def __init__(self, match_id):
self.followon = self._followon()
def _followon(self):
try:
if self.match_json()['followon'] == '1':
return True
except:
else:
return False
我在后续函数的 else 块中遇到缩进错误
整个 if/else
语句需要放在 try
部分中。我认为最好的方法是做这样的事情:
class MyMatch(object):
def __init__(self, match_id):
self.followon = self._followon()
def _followon(self):
try:
# Bellow code will return:
# True when self.match_json()['followon'] == '1'
# False when self.match_json()['followon'] != '1'
return bool(self.match_json()['followon'] == '1')
except KeyError:
# This will return False when for example match_json()
# does not have a 'followon' key
return False
您的条件应该在 try 块内。改成这种格式
try:
if self.match_json()['followon'] == '1':
return True
else:
return False
except:
pass
我的 class MyMatch 中有函数列表,在函数
中组合 try except 和 if else 时出现缩进错误这是我的比赛Class
class MyMatch(object):
def __init__(self, match_id):
self.followon = self._followon()
def _followon(self):
try:
if self.match_json()['followon'] == '1':
return True
except:
else:
return False
我在后续函数的 else 块中遇到缩进错误
整个 if/else
语句需要放在 try
部分中。我认为最好的方法是做这样的事情:
class MyMatch(object):
def __init__(self, match_id):
self.followon = self._followon()
def _followon(self):
try:
# Bellow code will return:
# True when self.match_json()['followon'] == '1'
# False when self.match_json()['followon'] != '1'
return bool(self.match_json()['followon'] == '1')
except KeyError:
# This will return False when for example match_json()
# does not have a 'followon' key
return False
您的条件应该在 try 块内。改成这种格式
try:
if self.match_json()['followon'] == '1':
return True
else:
return False
except:
pass