计算具有子查询的两个 table 的并集

Question

我有这个工作查询。它有子查询计数。

SELECT 
  COUNT(*) AS total 
FROM
  (SELECT 
    COUNT(aset) 
  FROM
    `public_1` 
  WHERE `public_1`.`aset` NOT IN 
    (SELECT 
      asset_code 
    FROM
      application_detail 
    WHERE application_id = 6) 
    AND org_id = 7 
    AND status_id = 8 
  GROUP BY aset) t

现在我需要合并不同的 table 并从两个 table 中获取总数。此代码可以获取计数记录，但值不正确。

SELECT 
  COUNT(*) AS total 
FROM
  (SELECT 
    COUNT(aset) 
  FROM
    `public_1` 
  WHERE `public_1`.`aset` NOT IN 
    (SELECT 
      asset_code 
    FROM
      application_detail 
    WHERE application_id = 6) 
    AND org_id = 7 
    AND status_id = 8 
  UNION
  SELECT 
    COUNT(aset) 
  FROM
    `public_2` 
  WHERE `public_2`.`aset` NOT IN 
    (SELECT 
      asset_code 
    FROM
      application_detail 
    WHERE application_id = 6) 
    AND org_id = 7 
    AND status_id = 8 
  GROUP BY aset) z

请帮助我正确查询。提前致谢

Answer 1

使用 SELECT COUNT(DISTINCT aset) 计算您的计数，然后将它们相加。

SELECT t1.total + t2.total AS total
FROM (
    SELECT COUNT(DISTINCT aset) AS total
    FROM `public_1` 
    WHERE `public_1`.`aset` NOT IN 
        (SELECT 
          asset_code 
        FROM
          application_detail 
        WHERE application_id = 6) 
        AND org_id = 7 
        AND status_id = 8) AS t1
CROSS JOIN (
    SELECT COUNT(DISTINCT aset) AS total
    FROM `public_2` 
    WHERE `public_2`.`aset` NOT IN 
        (SELECT 
          asset_code 
        FROM
          application_detail 
        WHERE application_id = 6) 
        AND org_id = 7 
        AND status_id = 8) AS t2

计算具有子查询的两个 table 的并集

Count union of two table that has subquery

mysql

union

notin