Parse error: syntax error unexpected end of file in php
Parse error: syntax error unexpected end of file in php
这是我的代码,我检查了所有右大括号和左大括号,我也没有在任何地方使用它的缩写 php 并且我不会错过 ';',
我不知道为什么它显示解析错误:
<html>
<head>
<script type="text/javascript" src="<?php echo base_url('assests/js/jquery.min.js') ?>"></script>
<link rel="stylesheet" type="text/css" href="<?php echo base_url('assests/css/bootstrap.min.css') ?>">
<script type="text/javascript" src="<?php echo base_url('assests/js/bootstrap.min.js') ?>"></script>
</head>
<body>
<div class="container">
<table class="hover hover-table">
<tr>
<th>No</th>
<th>Code</th>
<th>Name</th>
<th>Address</th>
</tr>
<?php if(count($all_user>0))
{ $i=0;
foreach ($all_user as $user)
{
$i++;
?>
<tr>
<td><?php echo $i ?></td>
<td><?php echo $user->code ?></td>
<td><?php echo $user->name?></td>
<td><?php echo $user->address ?></td>
</tr>
}
}
</table>
</div>
</body>
</html>
您在花括号 <?php }}
之前缺少结束 php 标记。因此你得到 Line : 36 -- syntax error, unexpected end of file
试试这个方法,
<html>
<head>
<script type="text/javascript" src="<?php echo base_url('assests/js/jquery.min.js') ?>"></script>
<link rel="stylesheet" type="text/css" href="<?php echo base_url('assests/css/bootstrap.min.css') ?>">
<script type="text/javascript" src="<?php echo base_url('assests/js/bootstrap.min.js') ?>"></script>
</head>
<body>
<div class="container">
<table class="hover hover-table">
<tr>
<th>No</th>
<th>Code</th>
<th>Name</th>
<th>Address</th>
</tr>
<?php if(count($all_user>0))
{ $i=0;
foreach ($all_user as $user)
{
$i++;
?>
<tr>
<td><?php echo $i ?></td>
<td><?php echo $user->code ?></td>
<td><?php echo $user->name?></td>
<td><?php echo $user->address ?></td>
</tr>
<?php
}
}
?>
</table>
</div>
</body>
</html>
您缺少打开和关闭php
</tr>
<?php } /* endforeach */
} /* endif */ ?>
</table>
这就是您遇到错误的原因。
这是我的代码,我检查了所有右大括号和左大括号,我也没有在任何地方使用它的缩写 php 并且我不会错过 ';',
我不知道为什么它显示解析错误:
<html>
<head>
<script type="text/javascript" src="<?php echo base_url('assests/js/jquery.min.js') ?>"></script>
<link rel="stylesheet" type="text/css" href="<?php echo base_url('assests/css/bootstrap.min.css') ?>">
<script type="text/javascript" src="<?php echo base_url('assests/js/bootstrap.min.js') ?>"></script>
</head>
<body>
<div class="container">
<table class="hover hover-table">
<tr>
<th>No</th>
<th>Code</th>
<th>Name</th>
<th>Address</th>
</tr>
<?php if(count($all_user>0))
{ $i=0;
foreach ($all_user as $user)
{
$i++;
?>
<tr>
<td><?php echo $i ?></td>
<td><?php echo $user->code ?></td>
<td><?php echo $user->name?></td>
<td><?php echo $user->address ?></td>
</tr>
}
}
</table>
</div>
</body>
</html>
您在花括号 <?php }}
之前缺少结束 php 标记。因此你得到 Line : 36 -- syntax error, unexpected end of file
试试这个方法,
<html>
<head>
<script type="text/javascript" src="<?php echo base_url('assests/js/jquery.min.js') ?>"></script>
<link rel="stylesheet" type="text/css" href="<?php echo base_url('assests/css/bootstrap.min.css') ?>">
<script type="text/javascript" src="<?php echo base_url('assests/js/bootstrap.min.js') ?>"></script>
</head>
<body>
<div class="container">
<table class="hover hover-table">
<tr>
<th>No</th>
<th>Code</th>
<th>Name</th>
<th>Address</th>
</tr>
<?php if(count($all_user>0))
{ $i=0;
foreach ($all_user as $user)
{
$i++;
?>
<tr>
<td><?php echo $i ?></td>
<td><?php echo $user->code ?></td>
<td><?php echo $user->name?></td>
<td><?php echo $user->address ?></td>
</tr>
<?php
}
}
?>
</table>
</div>
</body>
</html>
您缺少打开和关闭php
</tr>
<?php } /* endforeach */
} /* endif */ ?>
</table>
这就是您遇到错误的原因。