使用 "AND" 运算符的多个条件和使用 MySQL 来自单个 table 的 return 精确匹配行

Question

select 
  games_exchange.u_exchange_id 
from 
  games_exchange 
where  
  ( games_exchange.game_id = 7 
  AND games_exchange.exchange_type = 1 )
  AND (
  games_exchange.game_id = 7 
  AND games_exchange.exchange_type = 2 )
group by 
  games_exchange.u_exchange_id 
HAVING 
  COUNT( games_exchange.u_exchange_id ) = 2

我对上述查询的预期结果是 u_exchange_id = 171。但是上面的查询 return u_exchange_id = 171 & 170.

[table 的屏幕截图在此处][2]

Answer 1

经过大量研究，我找到了解决问题的办法。实际上，我在使用 having 子句时错误地使用了 where 条件。 针对我的问题提出的解决方案在下面的代码中给出

SELECT u_exchange_id FROM games_exchange 
WHERE 
u_exchange_id IN 
( SELECT u_exchange_id FROM games_exchange WHERE game_id = 7 AND 
exchange_type = 1 )
AND 
u_exchange_id IN 
( SELECT u_exchange_id FROM games_exchange WHERE game_id = 7 AND 
exchange_type = 2)
GROUP BY u_exchange_id 
HAVING COUNT( u_exchange_id ) = 2

Note: I achieved this by using foreach() on games ids of both section and I added dynamically sub-query for every id.

使用 "AND" 运算符的多个条件和使用 MySQL 来自单个 table 的 return 精确匹配行

Multiple condition using "AND" operator and return exact matching rows from a single table using MySQL

mysql

sql

sql-server

exact-match