Laravel 5.7 - 未定义的偏移量:1
Laravel 5.7 - Undefined offset: 1
我是 Laravel 的新人,这是我的第一个问题。
我有 3 个表:
类别:id、姓名(目前有 2 项)
变体:id、name
category_variant:id,category_id,variant_id; <--
每个变体都有 1 或 2 个类别
在 VariantController 中,我有以下代码:
public function edit($id)
{
$variant = Variant::where('id', $id)->with('categories')->first();
$categories = Category::all();
return view('admin.variant.edit', compact('variant', 'categories'));
}
在 edit.blade.php 我有以下 html:
@foreach ($categories as $key=>$category)
<div class="form-group form-float">
@if (isset($variant->categories[$key]->pivot->category_id)) <-- I think here is the problem
<input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}" {{ $category->id == $variant->categories[$key]->pivot->category_id ? 'checked' : ''}} >
<label for="wb">{{ $category->name}}</label>
@else
<input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}">
<label for="wb">{{ $category->name}}</label>
@endif
</div>
@endforeach
我想知道在复选框中选中了哪个类别。如果变体具有所有 2 个类别,一切正常,但如果用户只选择了一个类别,我会收到错误消息
Undefined offset: 1 (View: /shui/resources/views/admin/variant/edit.blade.php)
我该如何解决这个问题?
提前致谢
迪米
你可以使用collection的力量:
@if($variant->categories->contains($category))
{{-- You does not need to test a second time to know if you need to "check" --}}
<input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}" checked >
<label for="wb">{{ $category->name}}</label>
@else
{{-- Do stuff --}}
@endif
或者更简单。删除第一个 @if
<input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}" $variant->categories->contains($category)? 'checked' : '' >
<label for="wb">{{ $category->name}}</label>
同样在你的Controller中,你可以简化
$variant = Variant::where('id', $id)->with('categories')->first();
和
$variant = Variant::with('categories')->find($id);
// Or better, Laravel throws a 404 error when the id doesn't exists
$variant = Variant::with('categories')->findOrFail($id);
我是 Laravel 的新人,这是我的第一个问题。 我有 3 个表:
类别:id、姓名(目前有 2 项)
变体:id、name
category_variant:id,category_id,variant_id; <-- 每个变体都有 1 或 2 个类别
在 VariantController 中,我有以下代码:
public function edit($id)
{
$variant = Variant::where('id', $id)->with('categories')->first();
$categories = Category::all();
return view('admin.variant.edit', compact('variant', 'categories'));
}
在 edit.blade.php 我有以下 html:
@foreach ($categories as $key=>$category)
<div class="form-group form-float">
@if (isset($variant->categories[$key]->pivot->category_id)) <-- I think here is the problem
<input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}" {{ $category->id == $variant->categories[$key]->pivot->category_id ? 'checked' : ''}} >
<label for="wb">{{ $category->name}}</label>
@else
<input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}">
<label for="wb">{{ $category->name}}</label>
@endif
</div>
@endforeach
我想知道在复选框中选中了哪个类别。如果变体具有所有 2 个类别,一切正常,但如果用户只选择了一个类别,我会收到错误消息
Undefined offset: 1 (View: /shui/resources/views/admin/variant/edit.blade.php)
我该如何解决这个问题? 提前致谢 迪米
你可以使用collection的力量:
@if($variant->categories->contains($category))
{{-- You does not need to test a second time to know if you need to "check" --}}
<input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}" checked >
<label for="wb">{{ $category->name}}</label>
@else
{{-- Do stuff --}}
@endif
或者更简单。删除第一个 @if
<input type="checkbox" id="wb" class="filled-in" name="wb" value="{{$category->id}}" $variant->categories->contains($category)? 'checked' : '' >
<label for="wb">{{ $category->name}}</label>
同样在你的Controller中,你可以简化
$variant = Variant::where('id', $id)->with('categories')->first();
和
$variant = Variant::with('categories')->find($id);
// Or better, Laravel throws a 404 error when the id doesn't exists
$variant = Variant::with('categories')->findOrFail($id);