Flask send_file 未发送文件

Question

我将 Flask 与 send_file() 结合使用，让人们从服务器下载文件。

我目前的代码如下：

@app.route('/', methods=["GET", "POST"])
def index():
    if request.method == "POST":
        link = request.form.get('Link')
        with youtube_dl.YoutubeDL(ydl_opts) as ydl:
            info_dict = ydl.extract_info(link, download=False)
            video_url = info_dict.get("url", None)
            video_id = info_dict.get("id", None)
            video_title = info_dict.get('title', None)
            ydl.download([link])
        print("sending file...")
        send_file("dl/"+video_title+".f137.mp4", as_attachment=True)
        print("file sent, deleting...")
        os.remove("dl/"+video_title+".f137.mp4")
        print("done.")
        return render_template("index.html", message="Success!")
    else:
        return render_template("index.html", message=message)

我添加 .f137.mp4 的唯一原因是因为我使用 AWS C9 作为我的在线 IDE 并且我无法安装 FFMPEG 来组合亚马逊上的音频和视频 Linux.但是，这不是问题。问题是它没有发送下载请求。

控制台输出如下：

127.0.0.1 - - [12/Dec/2018 16:17:41] "POST / HTTP/1.1" 200 -
[youtube] 2AYgi2wsdkE: Downloading webpage
[youtube] 2AYgi2wsdkE: Downloading video info webpage
[youtube] 2AYgi2wsdkE: Downloading webpage
[youtube] 2AYgi2wsdkE: Downloading video info webpage
WARNING: You have requested multiple formats but ffmpeg or avconv are not installed. The formats won't be merged.
[download] Destination: dl/Meme Awards v244.f137.mp4
[download] 100% of 73.82MiB in 00:02
[download] Destination: dl/Meme Awards v244.f140.m4a
[download] 100% of 11.63MiB in 00:00
sending file...
file sent, deleting...
done.
127.0.0.1 - - [12/Dec/2018 16:18:03] "POST / HTTP/1.1" 200 -

感谢您提供的所有帮助。谢谢！

Answer 1

您需要 return send_file 的结果：

@app.route('/', methods=["GET", "POST"])
def index():
    if request.method == "POST":
        link = request.form.get('Link')
        with youtube_dl.YoutubeDL(ydl_opts) as ydl:
            info_dict = ydl.extract_info(link, download=False)
            video_url = info_dict.get("url", None)
            video_id = info_dict.get("id", None)
            video_title = info_dict.get('title', None)
            ydl.download([link])
        print("sending file...")
        return send_file("dl/"+video_title+".f137.mp4", as_attachment=True)
    else:
        return render_template("index.html", message=message)

不幸的是，这会让您在发送文件后更难 "clean up"，因此您可能希望将其作为定期维护的一部分（例如运行一个 cron 作业来删除旧文件下载的文件）。有关此问题的详细信息，请参阅。

Answer 2

正如 Rob Bricheno 所说，

You need to return the result of send_file

所以你可以保存"flask.send_file"的结果，然后清理，然后return结果。

print("sending file...")
result = send_file("dl/"+video_title+".f137.mp4", as_attachment=True)
print("file sent, deleting...")
os.remove("dl/"+video_title+".f137.mp4")
return result

Answer 3

扩展@Rob Bricheno的回答，如果你需要在请求后清理，你可以创建一个延迟方法，在请求完成后执行：

@app.route('/', methods=["GET", "POST"])
def index():
    if request.method == "POST":
        link = request.form.get('Link')
        with youtube_dl.YoutubeDL(ydl_opts) as ydl:
            info_dict = ydl.extract_info(link, download=False)
            video_url = info_dict.get("url", None)
            video_id = info_dict.get("id", None)
            video_title = info_dict.get('title', None)
            ydl.download([link])
        print("sending file...")
        response = send_file("dl/"+video_title+".f137.mp4", as_attachment=True)
        # Create handle for processing display results (non-blocking, excecutes after response is returned)
        @flask.after_this_request
        def add_close_action(response):
            @response.call_on_close
            def process_after_request():
                try:
                    print("file sent, deleting...")
                    os.remove("dl/"+video_title+".f137.mp4")
                    print("done.")
                except Exception as e:
                    logger.exception(str(e))
        return response
    else:
        return render_template("index.html", message=message)

Flask send_file 未发送文件

Flask send_file not sending file

python

ffmpeg

flask

youtube-dl