Java

Question

给定这个日期我想解析：12 月 15 日 16:00 +01:00

使用此代码

    Map<Long, String> ordinalNumbers = new HashMap<>(42);
    ordinalNumbers.put(1L, "1st");
    ordinalNumbers.put(2L, "2nd");
    ordinalNumbers.put(3L, "3rd");
    ordinalNumbers.put(21L, "21st");
    ordinalNumbers.put(22L, "22nd");
    ordinalNumbers.put(23L, "23rd");
    ordinalNumbers.put(31L, "31st");
    for (long d = 1; d <= 31; d++) {
        ordinalNumbers.putIfAbsent(d, "" + d + "th");
    }

    DateTimeFormatter formatter = new DateTimeFormatterBuilder()
            .appendText(ChronoField.DAY_OF_MONTH, ordinalNumbers)
            .appendPattern(" MMM HH:mm[:ss] xxx")
            .parseDefaulting(ChronoField.SECOND_OF_MINUTE, 0)
            .toFormatter().withLocale(Locale.ENGLISH);

    ZonedDateTime eventDate = ZonedDateTime.parse("15th Dec 16:00 +01:00", formatter);

但我总是得到

java.time.DateTimeException: Unable to obtain ZonedDateTime from TemporalAccessor: {DayOfMonth=15, MonthOfYear=12, OffsetSeconds=3600},ISO resolved to 16:00 of type java.time.format.Parsed

您可以在此处在线试用：https://repl.it/repls/NaiveRegularEquation 请告诉我我做错了什么。

更新：缺少年份是问题所在。

 DateTimeFormatter formatter = new DateTimeFormatterBuilder()
            .appendText(ChronoField.DAY_OF_MONTH, ordinalNumbers)
            .appendPattern(" MMM HH:mm[:ss] xxx")
            .parseDefaulting(ChronoField.YEAR, 2018)
            .parseDefaulting(ChronoField.SECOND_OF_MINUTE, 0)
            .toFormatter().withLocale(Locale.ENGLISH);

Answer 1

指定年份

ZonedDateTime 需要一个年份字段，而您没有提供。

您可以设置默认值：

DateTimeFormatter formatter = new DateTimeFormatterBuilder()
        .parseDefaulting(ChronoField.YEAR_OF_ERA, ZonedDateTime.now().getYear()) // set default year
        .appendText(ChronoField.DAY_OF_MONTH, ordinalNumbers)
        .appendPattern(" MMM HH:mm[:ss] xxx")
        .parseDefaulting(ChronoField.SECOND_OF_MINUTE, 0)
        .toFormatter().withLocale(Locale.ENGLISH);

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