无法获取 Ajax 以更新按 GROUP CONCAT 分组的 MySQL 行结果。有可能吗？

Question

我设法让 Ajax 通过单击我要更新的条目来动态更新 MySQL 行结果，这很有效。但是，如果我使用 GROUP CONCAT，我仍然可以单击要更新的条目，但不会保存更改。这是正常的吗？或者这仍然适用于 GROUP CONCAT 吗？

当 mysql 查询不使用组连接时有效的当前代码：

这是函数：

function edit_data(id, text, column_name)  
{  
$.ajax({  
url:"food_edit.php",  
method:"POST",  
data:{id:id, text:text, column_name:column_name},  
dataType:"text",  
success:function(data){  
//alert(data);
}  
});  
}

这是food_edit.php

<?php
include ("expenses.inc");
session_start(); 

$con = mysqli_connect("$server","$user","$pw","$db");   

$id = $_POST["id"];  
$text = $_POST["text"];  
$column_name = $_POST["column_name"];

$query = "UPDATE food SET ".$column_name."='".$text."'    WHERE id='".$id."'";
if(mysqli_query($con, $query))  
{  
echo 'Data Updated';  
}                                         
?>

我尝试按以下方式更新代码以补偿组连接但它不起作用：

function edit_data(ID, FOOD_TYPE, STORE_NAME, LOCATION, DATUM, COST)  
{  
$.ajax({  
url:"food_edit.php",  
method:"POST",  
data:{ID:ID, FOOD_TYPE:FOOD_TYPE, STORE_NAME:STORE_NAME, LOCATION:LOCATION, DATUM:DATUM, COST:COST},  
dataType:"text",  
success:function(data){  
//alert(data);
}  
});  
}

和food_edit.php：

<?php

include ("expenses.inc");

session_start(); 

$con = mysqli_connect("$server","$user","$pw","$db");   

$id = $_POST["id"];  

$FOOD_TYPE = $_POST["FOOD_TYPE"];
$STORE_NAME = $_POST["STORE_NAME"];
$LOCATION = $_POST["LOCATION"];
$DATUM = $_POST["DATUM"];
$COST = $_POST["COST"];

$query = "UPDATE food SET
".$FOOD_TYPE."='".$_POST["FOOD_TYPE"]."',
".$STORE_NAME."='".$_POST["STORE_NAME"]."',
".$LOCATION."='".$_POST["LOCATION"]."',
".$DATUM."='".$_POST["DATUM"]."',
".$COST."='".$_POST["COST"]."'

WHERE ID='".$_POST["ID"]."'";  

if(mysqli_query($con, $query))  
{  
echo 'Data Updated';  
}                                     
?>

希望这能说明问题。

我添加了带有组 concat

的 mysql 查询

$query = "
Select

GROUP_CONCAT(ID,' <br>' ORDER BY DATUM SEPARATOR ' ') AS ID,  

GROUP_CONCAT(FOOD_TYPE,' <br>' ORDER BY DATUM SEPARATOR ' ') AS FOOD_TYPE,  

GROUP_CONCAT(STORE_NAME,' <br>' ORDER BY DATUM SEPARATOR ' ') AS STORE_NAME,     

GROUP_CONCAT(LOCATION,' <br>' ORDER BY DATUM SEPARATOR ' ') AS LOCATION,

GROUP_CONCAT(DATUM,' <br>' ORDER BY DATUM SEPARATOR ' ') AS DATUM,   

GROUP_CONCAT(COST,' <br>' ORDER BY DATUM SEPARATOR ' ') AS COST 

FROM
(
SELECT food.ID, food.FOOD_TYPE, food.STORE_NAME, food.LOCATION, food.DATUM, food.COST FROM food
) TEST
group by DATUM
ORDER BY DATUM DESC";

Answer 1

查看您在后端调用什么来进行更改的示例会有所帮助，但我的猜测是您正在使用的 API 端点需要一个项目 ID，现在您正在提交多个。一般来说，更新不能包含任何分组，因为它们必须引用特定的行，分组可以通过子选择来完成。

无法获取 Ajax 以更新按 GROUP CONCAT 分组的 MySQL 行结果。有可能吗？

Cannot get Ajax to update MySQL row results grouped by GROUP CONCAT. Is it even possible?

php

ajax

mysqli

group-concat