Error when converting working code to a more object oriented structure Error: string indices must be integers Python 3

Question

我将运行放入错误中：在我的脚本中使用占位符时，字符串索引必须是整数。

我的程序应该纯粹根据计算来跟踪蔬菜的生长。这个想法是每个植物都有自己的特征（例如胡萝卜数据），但我没有为每个 'plantData' 编写代码，而是将代码替换为（whichPlant 和后来的 whichPlantData）作为临时占位符（这样我就不需要新的我花园里的每一种植物的代码，或者我想在以后添加的每一种植物的代码。

这是我在最后一行（植物是 class）中用 *** 标记的错误。当我使用 (carrotData) 而不是 (whichPlantData) 时，我的脚本有效。但是一旦我放入临时占位符 (whichPlantData) 就中断了。

这是什么原因造成的（这样我就可以避免在以后的项目中这样做），我该如何解决这个问题？

感谢支持！！

carrotData = {'plantID': '','plantingTime': dt(year=now.year, month=3, day=1), "dateOfPlanting": 0, "numberOfPlants": 0, "germinationTime": 7, "growthTime": 227, "flowerTime": 247, "harvestTime": 254, "liveCycles": 1, "status": 0}
potatoData = {'plantID': '','plantingTime': dt(year=now.year, month=3, day=1), "dateOfPlanting": 0, "numberOfPlants": 0, "germinationTime": 7, "growthTime": 227, "flowerTime": 247, "harvestTime": 254, "liveCycles": 1, "status": 0}

print ("imported plant datasheets")

#functions:

#if plant is added

def addPlant():
    whichPlant = input("Which plant do you want to add? ")
    n = int(input("How many plants do you want to add? "))
    i = 0
    whichPlantData = whichPlant + "Data"

    if whichPlant in inventory:
            while i < n:
                    i += 1
                    if whichPlant in plants:
                            plants[whichPlant] += 1
                    else:
                            plants[whichPlant] = 1
        ***Error*** whichPlant = Plant("", whichPlantData['plantingTime'], dt.now(), n, dt.now() + timedelta(days=whichPlantData['germinationTime']), dt.now() + timedelta(days=whichPlantData['growthTime']), dt.now() + timedelta(days=whichPlantData['flowerTime']),whichPlantData['harvestTime'], whichPlantData['liveCycles'], whichPlantData['status'])

Answer 1

您的问题似乎与 whichPlantData = whichPlant + "Data" 有关。 whichPlant 是由 input 函数返回的字符串。我认为您要做的是根据用户的输入获取植物信息字典。此外; whichPlant + "Data" 似乎试图使 whichPlant 与指向植物信息字典的变量名相同。仅仅因为字符串 whichPlant 可能等于变量名 carrotData 并不能使它与变量相同。我建议制作一个包含植物信息的字典列表，然后遍历该列表中的项目以查看字典 name 键是否与用户输入相同。类似这样：

plants = [{"Name": "Carrot", 'plantID': '','plantingTime':0, "dateOfPlanting": 0, "numberOfPlants": 0, "germinationTime": 7, "growthTime": 227, "flowerTime": 247, "harvestTime": 254, "liveCycles": 1, "status": 0},
{"Name": "Potato", 'plantID': '','plantingTime': 0, "dateOfPlanting": 0, "numberOfPlants": 0, "germinationTime": 7, "growthTime": 227, "flowerTime": 247, "harvestTime": 254, "liveCycles": 1, "status": 0}]

PlantName = input("Enter a Plant: ")

for plant in plants:
    if plant['Name'] == PlantName:
        print("{}'s germinationTime is {}".format(PlantName, plant["germinationTime"]))
        # DO SOMETHING

Error when converting working code to a more object oriented structure Error: string indices must be integers Python 3

Error when converting working code to a more object oriented structure Error: string indices must be integers Python 3

string

integer

indices

python-3.x